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17 l
P1V1=P2V2 VI=325ml P1=655mm Hg V2=125ml P2=? =655 x 325= P2 x 125 =(655 x 325)/ 125 =212875/125 =1703mm Hg. :)
To convert Torr to mm Hg, divide by 1.33. So, the partial pressure of helium in mm Hg is 439 Torr / 1.33 = 330 mm Hg. To find the partial pressure of hydrogen, subtract the partial pressure of helium from the total pressure: 600 mm Hg - 330 mm Hg = 270 mm Hg. Hence, the partial pressure of hydrogen gas is 270 mm Hg.
The volume is 0,046 L.
Peripheral pressure.
the answer is 72.1 Hg
False, normal blood pressure is a value of 120/80 mm Hg or lower.
The phrase "760 mm Hg" is physicists' shorthand for "an atmospheric pressure equal to that needed to support a column of mercury [chemical symbol Hg] of length 760 mm". This is approximately average atmospheric pressure at sea level. As the pressure decreases from "760 mm Hg" to "350 mm Hg", the volume of the gas will increase (assuming a constant temperature). The new volume can be determined using Boyle's Law: New Volume = 30 x 760 / 350 = 65.143 Litres
320.0 mm Hg
13.7, using P1V1T2=P2V2T1.
17 l
22.3 L
First two conversions: 609.5mm Hg = 0.8atm, and 117 deg. Celsius = 390 kelvins. Now, use the ideal gas law equation, PV=nRT with 0.082 as your value for R, the ideal gas constant: 0.8V=(0.7)(0.082)(390) and you get about 28L for the volume.
I'm not going to do all your work. The formula is Pressure1 X Volume 1 X Temperaure 1(in Kelvins)= Pressure 2 X Volume 2 X temperaure 2 So 3.97L X 1479mm Hg X 231.15K = y volume X 760mm Hg (1 atmosphere) X 293.15 (20 degrees C) I'll let you figure out the maths.
If we consider oxygen content in atmosphere to be roughly around 21% and the rest nitrogen then answer to the above question will be: 155.4 mm of Hg
P1V1=P2V2 VI=325ml P1=655mm Hg V2=125ml P2=? =655 x 325= P2 x 125 =(655 x 325)/ 125 =212875/125 =1703mm Hg. :)
7.41 L