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I'm not going to do all your work.

The formula is Pressure1 X Volume 1 X Temperaure 1(in Kelvins)= Pressure 2 X Volume 2 X temperaure 2

So 3.97L X 1479mm Hg X 231.15K = y volume X 760mm Hg (1 atmosphere) X 293.15 (20 degrees C)

I'll let you figure out the maths.

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Q: When a sample of nitrogen has a volume of 3.97 L at 1479 mm Hg and - 42 C what volume will it occupy at standard temperature and pressure?
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