Power is voltage times current. If there is no current, then there is no power. Without power, no work can be done, so the motor will do nothing.
In all probability, if this is happening to a motor, then there is an open circuit someplace, perhaps an open winding.
If you make the connection, the breaker on the generator will trip. The motor will not get up to running RPM. Check and see if the motor is dual voltage. If it is, run it on the higher voltage. This will reduce your run current to about half of what it is on the lower voltage.
No can do until you can provide the current rating in Amperes.
To calculate the starting current of a motor, the run current must be stated. The voltage is only associated with this calculation in as the higher the motor's voltage is the lower the run current is. The start current can be as high as 300 to 600 percent of the run current. Also taken into account, without the specific make and model of the A/C, the run current is hard to guess as there is quite a variety of amperage drawn by these units.
Only when you are Starting the car to turn the starter motor is the battery drawing current. Once the car starts, the alternator delivers the current and the voltage regulator regulates the voltage.
If you know the voltage and current then you can solve for the power: P = V*I
Low voltage release refers to the disconnection of a contactor and the stopping of the motor during power outage. This feature happens only with two-wire circuit.
Depends on what sort of motor it was. If it was the sort you find in an ordinary electric drill, then it would slow down. But rememer, the only way you can reasonably reduce the current in to motor is to reduce the voltage in the supply. A motor takes what current it can, dependent on Ohm's Law. To reduce the current, reduce the voltage. But in a three-phase motor, the speed being dependent on the rotation of the phases, it would more or less stay the same. But this assumes it's not under load. A load would cause it to slow down.
A rotating d.c. motor generates a back-emf which opposes the supply voltage and reduces the current drawn by the motor. When the motor is stationary, it cannot generate this back emf and, so, the only opposition to current is the resistance of its windings which is relatively low. So, on startup, the current is large; as the machine starts to run, the resulting back emf, acts to reduce the current.
Voltage flow into a starter motor, never out of it. Use the voltmeter to measure the voltage at the starter motor before starting to crank and then whilst it is cranking. (Before cranking, the voltage appears across the starter motor relay only.)
Compute the open load voltage of the current source across its shunt resistance.This voltage becomes the voltage source's voltage.Move the current source's shunt resistance to the voltage source's series resistance.Insert the new voltage source into the original circuit in place of the current source.
As long as you don't exceed the breakdown voltage of the capacitor ... which is marked right on it ... DC voltage on it produces NO current flow through it. Only AC 'appears' to flow through a capacitor, and even that appearance is bogus when you really get down to it.
RPS is only the voltage& power controlled device. it can only used for set the input for our wish A device which can change its output according to the voltage supplied to it is called a voltage controlled device.ex. a voltage controlled current source,or a field effect transistor. In a voltage controlled current source the output current changes as the voltage supplied to it changes.