What happens when aqueous solution of potassium iodide and lead acetate react?

When lead acetate reacts with potassium iodide then lead iodide PbI2 which is an yellow precipitate is formed. This is a double displacement reaction.The balanced chemical equation for this:-

Pb(CH3COO)2 + 2 KI = PbI2 + 2 K(CH3COO)