What happens when aqueous solution of potassium iodide and lead acetate react?
When lead acetate reacts with potassium iodide then lead iodide PbI2 which is an yellow precipitate is formed. This is a double displacement reaction.The balanced chemical equation for this:-
Pb(CH3COO)2 + 2 KI = PbI2 + 2 K(CH3COO)
It depends entirely upon the solid and the liquid. If you put a group 1 metal such as potassium into water you get a purple fireball, an explosion, hydrogen gas and potassium hydroxide. If you put potassium in oil nothing happens. If you put talc into water you get a suspension. If you put a salt into water you get an aqueous solution. Some things will react, others will not.
What happens when a solution of potassium iodide is added to a solution of lead nitrate taken in a test tube?
When chlorine gas is bubbled into an aqueous solution of potassium iodide, some of the iodide ions are oxidized to iodine. The iodine molecules combine with iodide ions to form brown triiodide ion, I3-. In this demonstration, the aqueous solution is above a layer of carbon tetrachloride, in which iodine is quite soluble. The beautiful violet color of iodine can be seen as the iodine dissolves in the carbon tetrachloride layer. With excess chlorine, iodine…
Whenever an acid reacts with an alkali, a salt and water are formed.This is a neutralization reaction i.e. acid + alkali --> salt +water In this case, nitric acid + potassium hydroxide --> potassium nitrate + water HNO3(aq) + KOH(aq) --> KNO3(aq) + H2O(l) Hence, a solution of potassium nitrate is formed.
I think what happens is a simple precipitation. Calcium acetate isn't soluble in ethanol, and hence crashes out of solution when ethanol is added to a saturated solution of calcium acetate. The precipitation is quick, leading to small strands of solid Ca(OAc)2, forming a solid gel. A gel consists of a continuous open network and a solvent. The network can be either solid or soluble in the solvent.