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Reddish precipitate of Mercuric iodide and clear solution of Potassium chloride is produced
Chlorine, a more reactive halogen would displace iodide in its hallide solution. Potassium chloride would be formed.
2K(I) + CuCl2 => 2KCl + Cu(I)2 The (I) is iodide, because the capital I and lowercase l look the same. This is a double replacement reaction, where copper (II) iodide comes out of solution, because it's not soluble, assuming that both of those are in solution.
In the laboratory, copper(I) Iodide is prepared by simply mixing an aqueous solutions of potassium iodide and a soluble copper(II) salt such copper sulphate. : :: Cu2+ + 2I− → CuI2 The CuI2 immediately decomposes to iodine and insoluble copper(I) iodide, releasing I2. : :: 2 CuI2 → 2 CuI + I2
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Worded Equation; Potassium Iodide + Calcium Chloride ------> Potassium Chloride + Calcium Iodide Chemical Equation; KI (l) + CaCl (l) -----> KCl (aq) + Ca(I)2 (aq) Note Answer is only correct if proper states are applied and used.
Potassium chloride and Iodine
monosodium glutamate, lead diacetate, potassium bitartrate, potassium chloride, magnesium sulfate, sodium chloride, uranyl nitrate, potassium phosphate, etc.
iodine and chloride ions
Sodium chloride (NaCl) is table salt. Additives may include potassium chloride and potassium iodide.
In aqueous solution they would not react. They would form a solution of ferric ions, chloride ions, potassium ions, and iodide ions.
It produces Potassium nitrate and Lead iodide