In the laboratory, copper(I) Iodide is prepared by simply mixing an aqueous solutions of potassium iodide and a soluble copper(II) salt such copper sulphate. : :: Cu2+ + 2I− → CuI2 The CuI2 immediately decomposes to iodine and insoluble copper(I) iodide, releasing I2. : :: 2 CuI2 → 2 CuI + I2
Potassium sulfate would be colorless; copper iodide is probably blue or green (I don't know which off the top of my head, but copper salts are generally either blue or green).
It produces Potassium nitrate and Lead iodide
2K(I) + CuCl2 => 2KCl + Cu(I)2 The (I) is iodide, because the capital I and lowercase l look the same. This is a double replacement reaction, where copper (II) iodide comes out of solution, because it's not soluble, assuming that both of those are in solution.
nothing
no reaction/no change
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Potassium sulfate would be colorless; copper iodide is probably blue or green (I don't know which off the top of my head, but copper salts are generally either blue or green).
General: 2KI + CuSO4 ----> CuI2 + K2SO4 The CuI2 immediately decomposes to iodine and insoluble copper(I) iodide, releasing I2.:: 2 CuI2 → 2 CuI + I2
It produces Potassium nitrate and Lead iodide
sugar, table salt, sodium sulphate, fructose, potassium chloride, potassium iodide, sodium iodide, uranyl nitrate, etc.
Pale green
2K(I) + CuCl2 => 2KCl + Cu(I)2 The (I) is iodide, because the capital I and lowercase l look the same. This is a double replacement reaction, where copper (II) iodide comes out of solution, because it's not soluble, assuming that both of those are in solution.
Nothing happens.
Silver iodide (AgI), a precipitate insoluble in water, don't react with potassium nitrate.
Nothing happens
nothing
holaaa lala