Cu+4HNO3 ----> Cu(NO3)2 + 2NO2 + 2H2O
The jar explodes immediately. Obviously, nitric acid mixed with glycerine is nitroglycerine (which is powerful explosive).
Bronze is an alloy that consists of copper and usually tin. When added to nitric acid, the nitrate anions attack the tin and copper cations to produce copper (II) nitrate and Tin (II) nitrate. Nitrogen monoxide is released but reacts with oxygen in the air to produce nitrogen dioxide.
Nitric acid. NO3 is the nitrate ion. When put into an acid the ate at the end changes to an ic. Therefore, HNO3 is nitric acid!
This reaction occurs in two steps. 1) Copper is oxidized by concentrated nitric acid. 3Cu + 2HNO3 = 3CuO + 2NO + H2O 2)The copper oxide is attacked by the excess HNO3: 3CuO + 6HNO3 = 3Cu(NO3)2 + 3H2O I put 3 CuO because there are 3 parts of CuO resulting from the first reaction and so, there are 3 parts of CuO reacting with the excess acid. Replacing the CuO with 3Cu(NO3)2 + 3H2O in the first equation, we have: 3Cu + 8HNO3 = 3Cu(NO3)2 + 2NO + 4H2O I put 8 parts of nitric acid because there are two parts that form the oxide and six parts that form the copper nitrate. There is also a second reaction, where NO reacts with oxygen in the air to form NO2, a very, very, very poisonous reddish-brown gas, but that's not part of the copper + nitric acid reaction
The acid becomes diluted.
The jar explodes immediately. Obviously, nitric acid mixed with glycerine is nitroglycerine (which is powerful explosive).
Bronze is an alloy that consists of copper and usually tin. When added to nitric acid, the nitrate anions attack the tin and copper cations to produce copper (II) nitrate and Tin (II) nitrate. Nitrogen monoxide is released but reacts with oxygen in the air to produce nitrogen dioxide.
Nitric acid. NO3 is the nitrate ion. When put into an acid the ate at the end changes to an ic. Therefore, HNO3 is nitric acid!
Provided it is yellow, put it in nitric acid. If not huing the acid, that is pure gold in contact with the acid
Nothing. Copper is not magnetic.
Yes, Copper oxide does fizz when it reacts with Sulphuric Acid
Any reaction occur when gold is put in copper sulfate.
This reaction occurs in two steps. 1) Copper is oxidized by concentrated nitric acid. 3Cu + 2HNO3 = 3CuO + 2NO + H2O 2)The copper oxide is attacked by the excess HNO3: 3CuO + 6HNO3 = 3Cu(NO3)2 + 3H2O I put 3 CuO because there are 3 parts of CuO resulting from the first reaction and so, there are 3 parts of CuO reacting with the excess acid. Replacing the CuO with 3Cu(NO3)2 + 3H2O in the first equation, we have: 3Cu + 8HNO3 = 3Cu(NO3)2 + 2NO + 4H2O I put 8 parts of nitric acid because there are two parts that form the oxide and six parts that form the copper nitrate. There is also a second reaction, where NO reacts with oxygen in the air to form NO2, a very, very, very poisonous reddish-brown gas, but that's not part of the copper + nitric acid reaction
When you put a metal inside sulphuric acid, the metal quickly displaces the hydrogen and forms respective metal sulphate and hydrogen gas is liberated. But this happens in the case of reactive metals only. In case of Mercury, Copper, Silver, Gold And Platinum no reaction occurs.
The acid becomes diluted.
Nothing happens. Gold will not react with sulfuric acid.
That was why i came here