NaCl
CH4
Methane (CH4) is a gas; the boiling point is at -164 0C.
The boiling point in degree Celsius are given below:Na: 883K: 774Si: 2355Ne: -246Silicon has the highest boiling point among the elements given.
Graphite by a long way
Yes, Boiling point of ammonia, NH3: - 33,34 0C Boiling poit of methane, CH4: - 161,6 0C
CH4
Methane (CH4) is a gas; the boiling point is at -164 0C.
The boiling point in degree Celsius are given below:Na: 883K: 774Si: 2355Ne: -246Silicon has the highest boiling point among the elements given.
CH4's melting point is -182 C. In the context of the usual type of question about melting points, CH4 has a very low melting point because the attractions between CH4 molecules are very weak.
Graphite by a long way
Metahne does not have a higher boiling point than methane. Fluoromethane, CH3F, has a boiling point of 195K, -78.2C, methane, CH4, has a boiling point of 109K approx -164 C. I make that fluoromethane has a higher temeprature boiling point than methane. This is what you would expect, London dispersion forces will be greater in CH3F as it has more electrons than CH4. CH3F is polar and there will be dipole dipole interactions which will not be present in CH4.
Yes, Boiling point of ammonia, NH3: - 33,34 0C Boiling poit of methane, CH4: - 161,6 0C
Think relationships here... really London Dispersion Force is like an acquaintance, Dipole Dipole is like boyfriend/girlfriend and Hydrogen Bonding is like marriage. Now out of the three London dispersion is the easiest to break the bonds, Di Pole Di pole are a little harder to break up and Hydrogen bonding are the hardest to break up the bonds. Hydrogen Bonding will always have the strongest bond. London dispersion is when for a split second their is a short attraction and doesn't last long. It is very weak therefore making this non- polar. Dipole Dipole means 2 opposite sides. Positive and negative charges. This molecule is a Polar molecule. Hydrogen Bonding is a Polar molecule which attaches itself to either N,O,or F. A melting point takes a low energy to melt so the bonds are weak. the higher the boiling temperature the stronger the bonds. Think H20. Melting is comparing how hard it is to separate the molecules. Same Concept. Ex.1.) CH4 / LiCl CH4 more soluable / LiCl low soluability CH4 low melting point / LiCL higher melting point CH4 low boiling point/ LiCL Higher boiling point CH4 London Dispersion / LiCl Dipole Dipole Example2: H2O / NaCl H2O high boiling point/ NaCl lower boiling point H2O Hydrogen bonding/ NaCl Dipole Dipol
Think relationships here... really London Dispersion Force is like an acquaintance, Dipole Dipole is like boyfriend/girlfriend and Hydrogen Bonding is like marriage. Now out of the three London dispersion is the easiest to break the bonds, Di Pole Di pole are a little harder to break up and Hydrogen bonding are the hardest to break up the bonds. Hydrogen Bonding will always have the strongest bond. London dispersion is when for a split second their is a short attraction and doesn't last long. It is very weak therefore making this non- polar. Dipole Dipole means 2 opposite sides. Positive and negative charges. This molecule is a Polar molecule. Hydrogen Bonding is a Polar molecule which attaches itself to either N,O,or F. A melting point takes a low energy to melt so the bonds are weak. the higher the boiling temperature the stronger the bonds. Think H20. Melting is comparing how hard it is to separate the molecules. Same Concept. Ex.1.) CH4 / LiCl CH4 more soluable / LiCl low soluability CH4 low melting point / LiCL higher melting point CH4 low boiling point/ LiCL Higher boiling point CH4 London Dispersion / LiCl Dipole Dipole Example2: H2O / NaCl H2O high boiling point/ NaCl lower boiling point H2O Hydrogen bonding/ NaCl Dipole Dipol
Look at intermolecular forces and judge from there
Chloromethane, or CH4, is a haloalkane, and the most abundant organohalogen in the atmosphere. It has a boiling point of -23.8 degrees Celsius.
H2O. Due to difference in electronegativity. O2 is covalent, NaCl and KI are ionic, CH4 is usually considered to be simply covalent as the electronegatiicty difference is small.