Graphite by a long way
CH4
Yes, Boiling point of ammonia, NH3: - 33,34 0C Boiling poit of methane, CH4: - 161,6 0C
Methane (CH4) is a gas; the boiling point is at -164 0C.
NaCl
Think relationships here... really London Dispersion Force is like an acquaintance, Dipole Dipole is like boyfriend/girlfriend and Hydrogen Bonding is like marriage. Now out of the three London dispersion is the easiest to break the bonds, Di Pole Di pole are a little harder to break up and Hydrogen bonding are the hardest to break up the bonds. Hydrogen Bonding will always have the strongest bond. London dispersion is when for a split second their is a short attraction and doesn't last long. It is very weak therefore making this non- polar. Dipole Dipole means 2 opposite sides. Positive and negative charges. This molecule is a Polar molecule. Hydrogen Bonding is a Polar molecule which attaches itself to either N,O,or F. A melting point takes a low energy to melt so the bonds are weak. the higher the boiling temperature the stronger the bonds. Think H20. Melting is comparing how hard it is to separate the molecules. Same Concept. Ex.1.) CH4 / LiCl CH4 more soluable / LiCl low soluability CH4 low melting point / LiCL higher melting point CH4 low boiling point/ LiCL Higher boiling point CH4 London Dispersion / LiCl Dipole Dipole Example2: H2O / NaCl H2O high boiling point/ NaCl lower boiling point H2O Hydrogen bonding/ NaCl Dipole Dipol
CH4
Metahne does not have a higher boiling point than methane. Fluoromethane, CH3F, has a boiling point of 195K, -78.2C, methane, CH4, has a boiling point of 109K approx -164 C. I make that fluoromethane has a higher temeprature boiling point than methane. This is what you would expect, London dispersion forces will be greater in CH3F as it has more electrons than CH4. CH3F is polar and there will be dipole dipole interactions which will not be present in CH4.
Yes, Boiling point of ammonia, NH3: - 33,34 0C Boiling poit of methane, CH4: - 161,6 0C
Methane (CH4) is a gas; the boiling point is at -164 0C.
CH4's melting point is -182 C. In the context of the usual type of question about melting points, CH4 has a very low melting point because the attractions between CH4 molecules are very weak.
NaCl
more electrons furthur down the group which means stronger van der waals forces exist so higher energy is needed to overcome these forces
CH3Cl because it is polar meaning it has both a dipole-dipole bond and dispersion bond, where as CCl4 is non polar and only has a dispersion bond. Since CH3Cl is bonded together stronger, it will be harder to break up and therefore a greater temperature will be required to boil it Edited (9/20/10) CCl4 has a bp 76.7 C, CH3Cl has a bp -24.2 C, see wikipedia or MSDS info. That means the first answer is wrong. Boiling points are based on intermolecular forces. Stronger the forces, lower the vapor pressure, higher the bp. The reason CCl4 has a higher boiling point is because dispersion forces increase with increasing molecular weight and # of electrons. Therefore the greater number of electrons in CCl4 create a stronger dispersion force than the combined dipole+dispersion forces in the CH3Cl.
CH3NH2 has the higher boiling point as it has a hydrogen bond between the molecule which is a stronger intermolecular attractive force, whereas CH3CH3 only has covalent bonds which are weaker intermolecular attractive forces.
Think relationships here... really London Dispersion Force is like an acquaintance, Dipole Dipole is like boyfriend/girlfriend and Hydrogen Bonding is like marriage. Now out of the three London dispersion is the easiest to break the bonds, Di Pole Di pole are a little harder to break up and Hydrogen bonding are the hardest to break up the bonds. Hydrogen Bonding will always have the strongest bond. London dispersion is when for a split second their is a short attraction and doesn't last long. It is very weak therefore making this non- polar. Dipole Dipole means 2 opposite sides. Positive and negative charges. This molecule is a Polar molecule. Hydrogen Bonding is a Polar molecule which attaches itself to either N,O,or F. A melting point takes a low energy to melt so the bonds are weak. the higher the boiling temperature the stronger the bonds. Think H20. Melting is comparing how hard it is to separate the molecules. Same Concept. Ex.1.) CH4 / LiCl CH4 more soluable / LiCl low soluability CH4 low melting point / LiCL higher melting point CH4 low boiling point/ LiCL Higher boiling point CH4 London Dispersion / LiCl Dipole Dipole Example2: H2O / NaCl H2O high boiling point/ NaCl lower boiling point H2O Hydrogen bonding/ NaCl Dipole Dipol
Think relationships here... really London Dispersion Force is like an acquaintance, Dipole Dipole is like boyfriend/girlfriend and Hydrogen Bonding is like marriage. Now out of the three London dispersion is the easiest to break the bonds, Di Pole Di pole are a little harder to break up and Hydrogen bonding are the hardest to break up the bonds. Hydrogen Bonding will always have the strongest bond. London dispersion is when for a split second their is a short attraction and doesn't last long. It is very weak therefore making this non- polar. Dipole Dipole means 2 opposite sides. Positive and negative charges. This molecule is a Polar molecule. Hydrogen Bonding is a Polar molecule which attaches itself to either N,O,or F. A melting point takes a low energy to melt so the bonds are weak. the higher the boiling temperature the stronger the bonds. Think H20. Melting is comparing how hard it is to separate the molecules. Same Concept. Ex.1.) CH4 / LiCl CH4 more soluable / LiCl low soluability CH4 low melting point / LiCL higher melting point CH4 low boiling point/ LiCL Higher boiling point CH4 London Dispersion / LiCl Dipole Dipole Example2: H2O / NaCl H2O high boiling point/ NaCl lower boiling point H2O Hydrogen bonding/ NaCl Dipole Dipol
Chloromethane, or CH4, is a haloalkane, and the most abundant organohalogen in the atmosphere. It has a boiling point of -23.8 degrees Celsius.