612.95
The weight of 2,5 mol of sulfuric acid is 245,1975 g.
196 grams H2SO4 (1 mole H2SO4/98.096 grams)(6.022 X 10^23/1 mole H2SO4) = 1.20 X 10^24 molecules of sulfuric acid
H2SO4 H= 1X2 = 2 S=32X1=32 O=16X4=64 TOTAL: 98 98x3= 294 GRAMS =))
The mol mass of sulfuric acid is 98.078 g/mol, 98 g of sulfuric acid therefore contains 0.9992 moles. Using consistent significant figures and your calculations, 98 g sulfuric acid would be equal to 1.0 mol sulfuric acid.
2 moles H2SO4 (98.086 grams/1 mole H2SO4)= 196.172 grams of sulfuric acid====================
612.95
The weight of 2,5 mol of sulfuric acid is 245,1975 g.
196 grams H2SO4 (1 mole H2SO4/98.096 grams)(6.022 X 10^23/1 mole H2SO4) = 1.20 X 10^24 molecules of sulfuric acid
2NH4OH + H2SO4 >> (NH4)2SO4 + 2H2O 8 moles NH4OH (1mol H2SO4/2mol NH4OH)(98.086g H2SO4/1mol H2SO4) = 392.34 grams H2SO4 needed
H2SO4 H= 1X2 = 2 S=32X1=32 O=16X4=64 TOTAL: 98 98x3= 294 GRAMS =))
The mol mass of sulfuric acid is 98.078 g/mol, 98 g of sulfuric acid therefore contains 0.9992 moles. Using consistent significant figures and your calculations, 98 g sulfuric acid would be equal to 1.0 mol sulfuric acid.
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Molarity = moles of solute/volume of solution ( so, not a great molarity expected ) 4.60 grams H2SO4 (1mol H2SO4/98.086g) = 0.0469 moles/450ml = 1.04 X 10^-4 Molarity.
0.010 moles The molar mass of H2SO4 is 98.1 grams per mole. To find out how many moles are present in a given mass, divide the mass by the molar mass. So: 1g/98.1g mol-1 is 0.010 mol.
17.9325 grams H2SO4 (1 mole H2SO4/98.086 grams(4 moles O/1 mole H2SO4)(6.022 X 1023/1 mole O) = 4.40387 X 1023 atoms of oxygen ======================
No such thing as HSO in chemistry. If you're referring to H2SO4, which is sulfuric acid, then 125 grams of it would be: H2SO4 = 98g/mol; 98/1=125/x; solve for x to get about 1.28 moles.