Molecular weight of CO2 is about 44g (12g Carbon + 32g Oxygen *2 atoms Oxygen). So that means if you are presented with 44g CO2, that means there's 12g Carbon.
1
32g
Carbon dioxide.
Carbon and oxygen.
The only thing I can think of is that 32g of Oxygen is 2 mol and 12g of Carbon is 1mol so 44g of Carbon di-Oxide (CO2) would have exactly 32g of Oxygen and 12g of Carbon.
Molecular weight of CO2 is about 44g (12g Carbon + 32g Oxygen *2 atoms Oxygen). So that means if you are presented with 44g CO2, that means there's 12g Carbon.
Molecular weight of CO2 is about 44g (12g Carbon + 32g Oxygen *2 atoms Oxygen). So that means if you are presented with 44g CO2, that means there's 12g Carbon.
Yes. CO2 has a weight of 44g/mol and O2 has a weight of 32g/mol.
1
32g
12g
12g
A sulfur dioxide has one sulfur atom and two oxygen atoms. Therefore, considering a mole of sulfur dioxide (64g); there is 32g of sulfur and 32g of oxygen. Hence the mass percent of oxygen is 50%.
44 grams of CO2 (1 mol CO2 from 1 mol C if enough oxygen, air, is available)
32g increased by 8% = 34.56g = 32g + (8% * 32g) = 32g + (0.08 * 32g) = 32g + 2.56g = 34.56g
It's all about ratios and moles.In 44g of CO2 32g is oxygen (2x16) and 12g is carbon (12). We can show that as a fraction 32/44 is oxygen.Your question asks for the mass of oxygen in 7.38g. Lets call the mass x (I love algebra). We are looking for a mass, x, out of 7.38 and we know how the ratios work in another example. So we can say:x/7.38 = 32/44Or, in English, if 32 out of 44 is oxygen, how much oxygen is in 7.38?We need to rearrange the equation to get x on it's own...x/7.38 = 32/44x = 32/44 *7.38x= 5.37gIt's difficult to explain it on the internet. If you still don't get it then please talk to your teacher. It's their job to explain it!