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Tr equals r what does r mean if t is not equal to 1?
r=0,Tr-r = 0 = r(T-1), since T != 1, then T-1 is non zero so r must be zero.
T equals R plus RS solve for R?
Given T = R + RS Lateral inversion makes it to be R + RS = T Taking R as common factor, we get R(1+S) = T Now dividing by (1+S) both sides, R = T / (1+S) Hence the solution R = T/(1+S)
What is the answer to 1 over R plus 1 over T?
(r+t)/rt
What is the formula for calculating a spot rate?
The formula is as follows:Because, in general, a zero-coupon bond price is...Z(t,T) = 1/[1+r(t,T)]TSO the spot rate would then equal...r(t,T) = [1/Z(t,T)1/T]-1
Growth model equation?
y=a(1+r)^t where a is the initial value, r is the rate as a decimal and t is the time in years.
If given the 10th term in the above geometric sequence which is 1536 what would you need to do to find the 11th term?
To find any term of a geometric sequence from another one you need the common ration between terms: t{n} = t{n-1} × r = t{1} × r^(n-1) where t{1} is the first term and n is the required term. It depends what was given in the geometric sequence ABOVE which you have not provided us. I suspect that along with the 10th term, some other term (t{k}) was given; in this case the common difference can be found: t{10} = 1536 = t{1} × r^9 t{k} = t{1} × r^(k-2) → t{10} ÷ t{k} = (t{1} × r^9) ÷ (t{1} × r^(k-1)) → t{10} ÷ t{k} = r^(10-k) → r = (t{10} ÷ t{k})^(1/(10-k)) Plugging in the values of t{10} (=1536), t{k} and {k} (the other given term (t{k}) and its term number (k) will give you the common ratio, from which you can then calculate the 11th term: t{11} = t(1) × r^9 = t{10} × r
How do you figure time on simple interest?
p = principal r= rate in decimal a =amount or final total t = time in years i = accumulated interest Simple interest: i=prt therefore t = i/pr Compound interest: a=(1+r)^t alright I'm going to throw in logs (logarithms) baby therefore log a = log ((1+r)^t)=t x log (1+r) therefore t = log a / log (1+r)
The first and fourth terms of a geometric progression are 54 and 2 respectively Find the sum to infinity of the geometric progression?
t(1) = a = 54 t(4) = a*r^3 = 2 t(4)/t(1) = r^3 = 2/54 = 1/27 and so r = 1/3 Then sum to infinity = a/(1 - r) = 54/(1 - 1/3) = 54/(2/3) = 81.
What is the nth term of an AP?
If the first term, t(1) = a and the common difference is r then t(n) = a + (n-1)*r where n = 1, 2, 3, ...
What is the binomial probability formula?
T r+1 = (n / r) (a ^n-r) x (b)^r
Given that T equals RV find R if T equals 4 and V equals 8?
T = RV 4 = R8 4/8 = R R = 1/2
How can you find the first term of an arithmetic sequence if you know the third and fifth terms?
Suppose A is the first term and R is common difference. Then, if t(n) is the nth term, t(n) = A + n*R Then t(5) = A + 5R and t(3) = A + 3R so that t(5) - t(3) = 2R Now t(1) = A + R = A + 3R - 2R (since R = 3R - 2R) So t(1) = t(3) - 2R You were given t(3) and have calculated 2R above, so can work out t(1).
