I dont no help
2Cu(s) + 2H2O(l) + O2(g) --> 2Cu(OH)2(s) is not a reaction which happens under any normal conditions. If it did we could say the copper is being oxidised.
Cu2 should be '2Cu' ( two uncombined atoms of copper.) O2- should be 'O2; ( 2 combined atoms of oxygen). When heated 2Cu(s) + O2(g) = 2CuO(s) CuO is copper oxide and appears as a black solid.
Exothermic, combustion
2Cu + O2 ---> 2CuOCopper + Oxygen ---> Copper II oxide
what is 2CU
2Cu(s)+O2(g) → 2CuO(s)
2Cu (s) + O2 (g) -----------------> 2CuO (s)
2Cu+O2 ---> 2CUO
I dont no help
The final answer would be 2Cu O2---> 2CuO
Oxidation
Cl2 + 2Cu --> 2CuCl Oxidation reaction is Cu --> Cu+ + 1e Reduction reaction is Cl + 1e --> Cl- Redox reaction is Cu + Cl --> Cu+ + Cl-
I think: (NH4)2Cu(SO4)2
SO4H2 + 2Cu --> SO2 + 2CuOH
2Cu(s) + O2(g) --> 2CuO(s)
2Cu(s) + 2H2O(l) + O2(g) --> 2Cu(OH)2(s) is not a reaction which happens under any normal conditions. If it did we could say the copper is being oxidised.