This looks very much like the first part of a chemical equation: the description of the process of a chemical reaction. The conventional rules for chemical equations are that - just like mathematical/algebraic equations - the two sides must match. KBr is Potassium Bromide; I2 is iodine, which in its natural state consists of two atoms joined together, and so is written with the subscript '2'. As one molecule of iodine has two atoms, two molecules of potassium bromide must be placed in the equation to make the sides match.
If these two substances are made to react (to my recollection, since bromine is more reactive than iodine this reaction would not occur unless catalyzed in some way, say by heat) then the iodine and bromide would change places, leaving potassium iodide and bromine (a brown, very pongy gas at room temperature); so the whole equation would be:
2 KBr + I2 -> 2 KI + Br2
it is unanswered
Bromine is the oxidizing element.
I2 + 10 hno3 = 2 hio3 + 10 no2 + 4 h2o
This is a trick question because "I2" is the chemical symbol for MOLECULAR iodine (your question did not say melt Iodine, it said melt I2).Only gaseous iodine is composed of I2 molecules and as it is a gas it CAN NOT melt.
Toward I2(s) production
2KI+Br2 ---->2KBr +I2
Br2(aq) + 2KI(aq) ==> 2KBr(aq) + I2(aq)
Its actually: 2KI(aq)+Br2(aq)-> I2(s)+2KBr(aq)
it is unanswered
Br2 (g) + 2 KI (aq) 2KBr (aq) + I2 (s)
2Na+I2-->2NaI
Br2 + 2KI -> 2KBr +I2
Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
(4 ± i2) where i2 = -1
Redox reaction.
4
2Mg + I2 ----> 2MgI