Be
In BeF2 the cation is Be2+.
3
BeCl2
Balanced equation for Sodium and Chlorine is: 2Na + Cl2 --> 2NaCl
The equation given is correctly balanced, because it contains the same numbers of each kind of atoms in the reactants as in the products.
2NaCl + F2 -- 2NaF + Cl2
F_2_ + 2NaCl yields 2NaF + Cl_2_
MgCl2(soln) + 2NaF(soln) ------> MgF2(s) + 2NaCl(aq)
BeCl2(aq) + 2NaOH(aq) -> 2NaCl(aq) + Be(OH)2(s) Be(aq) + 2OH(aq) -> Be(OH)2(s) Hope this helps!
The reaction i the following:2 NaCl + F2 = 2 NaF + Cl2
2NaCl + F2 -> 2NaF + Cl2 The first F in the equation has 2, so the second has to have 2 as well. But placing a 2 before the NaF, gives the Na 2. So add a 2 before the NaCl. and the Cl after the yield sign already has 2.
That is the (unbalanced) equation (substituting the "and" with an arrow) of the combination of salt and fluorine to create sodium fluoride and chlorine gas. Or...2NaCl + F2 → 2NaF + Cl2↑Sodium chloride + fluorine → sodium fluoride + chlorine gas
It's formula is BeF2 .
could be berylium tri fluoride hope that's riteA. that's not RIGHT.B. valence of Be is +2 , F is -1, thus the compound is BeF2 , berylium flouride.--------------------Actually, beryllium trifluoride is the correct name for the ionic compound with the formula as originally typed. It is commonly generated in situ from BeCl2 and NaF. Beryllium fluoride describes a different compound, BeF2.
becl2
BeCl2