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HCN(aq) ==> H^+(aq) + CN^-(aq)Ka = [H+][CN-]/[HCN] and the value can be looked up in a book or on line.
ka=[H+][NO2_]/[HNO2]
Kb = [CH3NH3 +] [OH-] / [CH3NH2]
Cr(s) | Cr3+(aq) Pb2+(aq) | Pb(s)
A precipitate
HCN(aq) ==> H^+(aq) + CN^-(aq)Ka = [H+][CN-]/[HCN] and the value can be looked up in a book or on line.
3.4 * 10^-8
Ka= [H+][NO2-] [HNO2]
ka=[H+][NO2_]/[HNO2]
not sure
Ka= [H+] [H2BO3-] / [h3BO3] (Apex)
Ka= [h+][HCO3-]/[H2CO3]
ka=[H+][NO2_]/[HNO2]
6.6 x 10-9
ka=[H+][CN-]/[HCN]
Net Ionic: Cd^+2+(aq) + S^2-(aq) ==> CdS(s)The Na^+ and Cl^- are spectator ions.
Cd^2+(aq) + 2Cl^-(aq) +2Na^+(aq) + S^2-(sq) ==> CdS(s) + 2Na^+(aq) + 2Cl^-(aq)The 2Na^+(aq) and the 2 Cl^-(aq) are spectator ions as they appear on both sides of the equation. Thus, the NET reaction is ...Cd^2+(aq) + S^2-(aq) ==> CdS(s)What else was your question. This is classed as a double replacement reaction.