Na2Cr2O7 (the formula is not Na2CrO7) is sodium dichromate.
Na2CrO4 is sodium chromate.
Sodium dichromate is a chemical compound , a salt, and has no net charge . It is ionic and contains Na+ and Cr2O72- ions
Sodium Dichromate
silver dichromate
Sodium chromate
Na2Cr2O7 is sodium dichromate.
Sodium Dichromate
sodium dichromate
It is Sodium Chromate Trihydrate.
Na2CrO4 is sodium chromate.
Na2CrO4 (aq) + 2LiOH (aq) -----> Li2CrO4 (s) + 2NaOH (aq)
Li2Cr2O7 - lithium dichromate
74.3 g Na2CrO4 x 1 mole/162 g = 0.459 moles (3 sig figs)
Sodium Chromate
Na2CrO4 is sodium chromate.
Sodium chromate = Na2CrO4
Sodium dichromate has the formula Na2Cr2O7.
Na2CrO4 (aq) + 2LiOH (aq) -----> Li2CrO4 (s) + 2NaOH (aq)
Na2CrO4
Li2Cr2O7 - lithium dichromate
300.0 ml of water is added to .40 L of a .400 M Na2CrO4 solution what is the molarity of the resulting solution? Na2CrO4 = 2 Cr +Cr + 4 O's Molar mass = (2*23 + 52 + (4*16) = 162 A .400 M N Na2CrO4 solution has .400 moles of Na2CrO4 in a liter of water. .400 moles of Na2CrO4 = 0.400 * 162 = 64.8 grams of Na2CrO4 in a liter of water. Since you only have .40 L, you have 64.8 grams/liter * 0.4L = 25.92 grams of Na2CrO4 in 0.4 liter of solution. When you add 300.0 ml of water, you have total of 700 ml of solution. You still have 25.92 grams of Na2CrO4, but now you have 700 ml of solution. Molarity = moles of solute per liter of solution. Moles of solute = grams of solute ÷ Molar mass of solute Moles of solute = 25.92 ÷ 162 = 0.16 moles of Na2CrO4. Molarity = 0.16 moles of Na2CrO4 ÷ 0.700 L of solution. Molarity = 0.23 M
2NaAlO 2+3h2O
74.3 g Na2CrO4 x 1 mole/162 g = 0.459 moles (3 sig figs)
Sodium Chromate
3H2O has 6 hydrogen atoms and 3 oxygen atoms.
Na2CrO4 will dissolve in water as will all sodium compounds.