Sodium Chromate
The compound with the formula Na2CrO4 is called sodium chromate. It is a yellow crystalline solid that is commonly used in industrial processes such as producing pigments and as a corrosion inhibitor.
Na2CrO4 (aq) + 2LiOH (aq) -----> Li2CrO4 (s) + 2NaOH (aq)
Sodium chromate is the name of the compound Na2CrO4.
To find the number of moles of Na2CrO4 in 74.3 grams, you need to divide the given mass by the molar mass of Na2CrO4. The molar mass of Na2CrO4 is calculated by adding the atomic masses of all the elements: 2(Na) + Cr + 4(O). Then divide 74.3 grams by the molar mass of Na2CrO4 to get the number of moles.
It is soluble but does take a little effort to get it into solution.
The chemical formula of sodium chromate is Na2CrO4.
The chemical formula for sodium dichromate is Na2Cr2O7.
Na2CrO4
it is 106 grams it is 106 grams it is 106 grams
Sodium chromate usually does not contain any water molecules per formula. The formula for sodium chromate is Na2CrO4, which does not have any water molecules associated with it.
The compound with the formula Na2CrO4 is called sodium chromate. It is a yellow crystalline solid that is commonly used in industrial processes such as producing pigments and as a corrosion inhibitor.
Na2CrO4 (aq) + 2LiOH (aq) -----> Li2CrO4 (s) + 2NaOH (aq)
Sodium chromate is the name of the compound Na2CrO4.
balance equation of barrium chloride to sodium chromate
To find the number of moles of Na2CrO4 in 74.3 grams, you need to divide the given mass by the molar mass of Na2CrO4. The molar mass of Na2CrO4 is calculated by adding the atomic masses of all the elements: 2(Na) + Cr + 4(O). Then divide 74.3 grams by the molar mass of Na2CrO4 to get the number of moles.
It is soluble but does take a little effort to get it into solution.
The oxidation number of Na in Na2CrO4 is +1 and the oxidation number of O in Na2CrO4 is -2. To find the oxidation number of Cr, we let x be the oxidation number: 2(+1) + x + 4(-2) = 0 x = +6 Therefore, the oxidation number of Cr in Na2CrO4 is +6.