H2O(aq)+CO2(g)
Not directly. CrCl3 needs to be in a solution with water first. The addition of sodium carbonate will react with the solution forming hydroxide ions, which willreact with the Cr3+ ions in the solution to form a green precipitate, Cr(OH)3. CO3- = CO2 + O2- O2- + H2O = 2 OH- Cr3+ (aq) + 3OH- (aq) = Cr(OH)3
Co2(g) + h2o(g)Explanation apex
HCl(aq) + NaHCO3(s) --> NaCl(aq) + H2O(l) + CO2(g)
As the question is stated, the answer is zero, because there is no NaCl in 200 g, or any other amount, of H2O that can be "discovered".
H2O(aq)+CO2(g)
This equation is:C2H5OH + 3 O2 = 2 CO2 + 3 H2O
This is an exothermic reaction.
Not directly. CrCl3 needs to be in a solution with water first. The addition of sodium carbonate will react with the solution forming hydroxide ions, which willreact with the Cr3+ ions in the solution to form a green precipitate, Cr(OH)3. CO3- = CO2 + O2- O2- + H2O = 2 OH- Cr3+ (aq) + 3OH- (aq) = Cr(OH)3
Co2(g) + h2o(g)Explanation apex
HCl(aq) + NaHCO3(s) --> NaCl(aq) + H2O(l) + CO2(g)
OH- + H+ H2O
As the question is stated, the answer is zero, because there is no NaCl in 200 g, or any other amount, of H2O that can be "discovered".
Youwill getCO2 (g) + H2O (l) + NaCL(aq)don't forget to balance the equation!!!
0.630 g NaCl x (1 mol NaCl/58.44 g NaCl) = 0.0108 mol NaCl525 g H2O x (1 kg/1000g) = 0.525 kg H2O0.0108 mol NaCl/0.525 kg H2O = 0.0206 molality
yes reactants: NaHCO3(s) + HCl(aq) + heat products: NaCl(aq) + H2O(l) + CO2(g)
Methane , CH4 , is a fuel that can react with O2 to yield CO2, H2O, and heat. CH4 (g) + O2 (g) ----> CO2 (g) + 2 H2O (g) + Heat