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What is V1 V2 and VTOT?

Updated: 12/19/2022
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Q: What is V1 V2 and VTOT?
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Why there is algebric sum of the resistances in the series combination?

Ohms Law will be helpful in seeing how resistances add up. Let's assume you have a 10 ohm and a 20 ohm resistor in series and 30 Volts. across the series. Ohm's Law states that Voltage = Resistance x Current. If we describe the 10 ohm resistor as R1 and the other as R2 then the voltage drop across R1 is V1 and V2 is the drop across R2. This can be written V1 = R1 x I1 and V2 = R2 x I2. Since the total voltage must equal the sum of the voltage drops then Vtot = V1 + V2. Also Itot = I1 + I2. Substituting we get Vtot = (I1 x R1) + (I2 x R2) = (I1 + I2) x (R1 + R2). And Vtot = Itot x Rtot so Rtot = R1 + R2. In example 30 Volts = Itot x (10 + 20) or Itot = 1 amp.


In the acceleration equation what do v1 and v2 represent?

v1 = initial velocity v2 = final velocity


What is the equation for the percentage difference of 20 and 31?

( | V1 - V2 | / ((V1 + V2)/2) ) * 100


What is the v1 v2 and rotate speed on a dc3?

v1 is design speed and v2 rotation speed


What is the formula for percentage change?

[ ((v2 - v1) / |v1|) * 100 ]


Will changing the order of your displacements in the vector diagram affect magnitude and direction?

No. Result= V1 + V2 = V2 + V1.


What is the average velocity when a person traveling on a straight line moves with a uniform velocity v1 for x distance and v2 for next equal distance?

Let t1 and t2 be the times for the two stages. Then t1 = x/v1 and t2 = x/v2 Total distance = x + x = 2x Total time = t1 + t2 = x/v1 + x/v2 = x*(1/v1 + 1/v2) Average velocity = total distance / total time = 2x divided by x/(1/v1 + 1/v2) = 2(1/v1 + 1/v2) which is the Harmonic mean of v1 and v2.


Difference between of rip v1 and rip v2?

Rip V1 is Classful routing protocol Rip V2 is Classless routing Protocol


How do you prepare 5 picomole solution from 32nanomole solution?

5 * 10**-12 mol 32 * 10**-9 mol Concentration (M) * Volume (L) = mols C1*V1=C2*V2 (5*10**-12)*V1=(32*10**-9)*V2 (5*10**-12)*V1/(32*10**-9)=V2 (5*10**-3)*V1/32=V2 The volume of the 5 picomolar solution that you wish take = V1 The volume of the 32 nanomolar solution that you need to make V1 at 5pM concentration = V2 Take V2, and place into graduated cylinder and fill to V1.


What is the advantage of a system with more than one type of output?

The most common multi output systems are used for getting differential output. i.e., if V1 and V2 are the 2 outputs, then usually the difference, V2-V1 or V1-V2 is used.


If acceleration=0, than according to "d=v2*t-1/2a*t^2" changed to get v2 is "v2=d+1/2a*t^2/t", but with acceleration=0, would v2=d V2=end velocity, d=distance, a=acceleration, t=time?

The equations of motion that relate velocity, distance, time and acceleration for the specific case of "constant acceleration" can be written as follow, acceleration a = (v2 - v1)/t from which v2 = v1 + at The distance covered during t time d = vav x t, where vav refers to average velocity in the process from v1 to v2. For the case of constant acceleration vav = (v1 + v2)/2. Substituting in d we get d = (v1 + v2)/2 x t from which, v2 = 2d/t - v1 If we take the constant acceleration to be zero, a = 0, you can see that the second equation we wrote becomes, v2 = v1 (There is no acceleration), so our equation for the distance d becomes, d = v1 x t = v2 x t


Why does work done is zero in isochoric process?

work done (by) the system equals zero , W=P(v2 - v1)= zero , where v2 = v1