Ohms Law will be helpful in seeing how resistances add up. Let's assume you have a 10 ohm and a 20 ohm resistor in series and 30 Volts. across the series. Ohm's Law states that Voltage = Resistance x Current. If we describe the 10 ohm resistor as R1 and the other as R2 then the voltage drop across R1 is V1 and V2 is the drop across R2. This can be written V1 = R1 x I1 and V2 = R2 x I2. Since the total voltage must equal the sum of the voltage drops then Vtot = V1 + V2. Also Itot = I1 + I2. Substituting we get Vtot = (I1 x R1) + (I2 x R2) = (I1 + I2) x (R1 + R2). And Vtot = Itot x Rtot so Rtot = R1 + R2. In example 30 Volts = Itot x (10 + 20) or Itot = 1 amp.
v1 = initial velocity v2 = final velocity
( | V1 - V2 | / ((V1 + V2)/2) ) * 100
v1 is design speed and v2 rotation speed
[ ((v2 - v1) / |v1|) * 100 ]
No. Result= V1 + V2 = V2 + V1.
Let t1 and t2 be the times for the two stages. Then t1 = x/v1 and t2 = x/v2 Total distance = x + x = 2x Total time = t1 + t2 = x/v1 + x/v2 = x*(1/v1 + 1/v2) Average velocity = total distance / total time = 2x divided by x/(1/v1 + 1/v2) = 2(1/v1 + 1/v2) which is the Harmonic mean of v1 and v2.
Rip V1 is Classful routing protocol Rip V2 is Classless routing Protocol
5 * 10**-12 mol 32 * 10**-9 mol Concentration (M) * Volume (L) = mols C1*V1=C2*V2 (5*10**-12)*V1=(32*10**-9)*V2 (5*10**-12)*V1/(32*10**-9)=V2 (5*10**-3)*V1/32=V2 The volume of the 5 picomolar solution that you wish take = V1 The volume of the 32 nanomolar solution that you need to make V1 at 5pM concentration = V2 Take V2, and place into graduated cylinder and fill to V1.
The most common multi output systems are used for getting differential output. i.e., if V1 and V2 are the 2 outputs, then usually the difference, V2-V1 or V1-V2 is used.
The equations of motion that relate velocity, distance, time and acceleration for the specific case of "constant acceleration" can be written as follow, acceleration a = (v2 - v1)/t from which v2 = v1 + at The distance covered during t time d = vav x t, where vav refers to average velocity in the process from v1 to v2. For the case of constant acceleration vav = (v1 + v2)/2. Substituting in d we get d = (v1 + v2)/2 x t from which, v2 = 2d/t - v1 If we take the constant acceleration to be zero, a = 0, you can see that the second equation we wrote becomes, v2 = v1 (There is no acceleration), so our equation for the distance d becomes, d = v1 x t = v2 x t
work done (by) the system equals zero , W=P(v2 - v1)= zero , where v2 = v1