2 Na + Br2 --> 2 NaBr
2 NaBr = 2 Na + Br2
The chemical equation is:3 NaOH + FeBr3 = 3 NaBr + Fe(OH)3
Any reaction occur between these compounds. For preparation:NaOH + HBr = NaBr + H2OKOH + HNO3 = KNO3 + H2OCaCl2 + H2S + CaS + 2 HCl
The melting point of NaBr is 747 oC.
There is actually 6Combustion: C10H8 + 12 O2 ---> 10 CO2 + 4 H2OSynthesis: 8 Fe + S8 ---> 8 FeSDecomposition: 2 H2O ---> 2 H2 + O2Single Decomposition: Mg + 2 H2O ---> Mg(OH)2 + H2Double Decomposition: Pb(NO3)2 + 2 KI ---> PbI2 + 2 KNO3Acid Base: HBr + NaOH ---> NaBr + H2O
There are two elements that make up the compound NaBr, or sodium bromide. These two elements are sodium and bromine.
Br2 + 3NaHSO3 = 2NaBr + NaHSO4 + H2O + 2SO2
This equation is Na2CO3 + 2 HCl -> 2 NaCl + CO2 (gas) + H2O.
The chemical equation is:3 NaOH + FeBr3 = 3 NaBr + Fe(OH)3
NiCl2 + 2 NaBr-----------NiBr2 + 2 NaCl
We know that the alkali metal sodium (Na) will form an ionic bond with the halogen bromine (Br) to create sodium bromide (NaBr). The equation looks like this: Na + Br => NaBr
The chemical equation is:3 NaOH + FeBr3 = 3 NaBr + Fe(OH)3
The chemical reaction is:Cl2 + 2 NaBr = 2 NaCl + Br2
NaBr
Sodium bromide
The chemical formula of sodium bromide is NaBr.
C4H9Br+NaOH > NaBr + C4H10O
This equation is 2 Na + Br2 -> 2 NaBr.