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No-Arg Constructor
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∙ 14y ago
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Default constructor in java?
If you don't type a constructor into your class code, a default constructor will be automatically generated by the compiler. The default constructor is ALWAYS a no-arg constructor. (Obviously the compiler has no clue what all arguments you might want for your class. So it takes the safe way out with a no argument constructor) A no-arg constructor is not necessarily the default (i.e., compiler-supplied) constructor, although the default constructor is always a no-arg constructor. The default constructor is the one the compiler provides! While the default constructor is always a no-arg constructor, you're free to put in your own no-arg constructor.
What is a default parameterized constructor?
There is no such thing as a default parameterized constructor. The default constructor is always the 'no-arg' constructor and does not take any parameters or arguments as input
How do you get a default constructor?
The default constructor is an empty (only call the super constructor) with no parameters constructor inserted by the java compiler when you don't define a constructor in your class. If you write something like this: public class NoConstructorClass{ //no constructor goes here } Then you get something like this: public class NoConstructorClass{ public NoConstructorClass(){ // Default constructor that you didn't write super(); } }
How is the default constructor equivalent to a constructor having default arguments?
Any constructor that can be invoked without explicitly passing any arguments is a default constructor. Note that there can be only one default constructor so there can only be one constructor where all arguments have default values or one constructor that has no arguments, but not both. A constructor where all arguments have default values is a useful means of combining two or more constructors into a single default constructor, thus reducing verbosity and code duplication.
When a object is passed to a function as argument why it is not generating an error if the parameterized constructor is defined and not the default constructor?
default constructor is used only when the programmer does not use a constructor to initialize objects. Once the programmer defines a constructor then the default constructor is no longer used
What is an empty constructor?
An empty constructor takes no arguments and calls the default constructor
Why Java always provides a default constructor to class when you use another constructor default constructor remove?
Classes in Java inherit constructors from their parent classes. If you don't explicitly define a parent class, then Object is used, which has only the default empty constructor. That "default" constructor is only there when defined by the parent class, so classes which do not have a no-argument constructor will not allow subclasses to automatically use it. This is implemented this way because of the special nature of constructors. Java could not always provide a default constructor because it could not guarantee that all class members would be properly created or initialized.
Using default constructor in inheritance and in what reason it throws error?
The compiler places a default no-arg constructor in any java class that does not have an explicit constructor coded into it. for ex: public class Car { ... ... //lots of code but no constructor } In the above case, the compiler will place the below constructor into the code: public Car() { super(); } But, if you have a constructor in your class that takes arguments then the compiler will not put the default constructor. Ex: public class Car { public Car(String name){ ... } ... //lots of code } Above, we have a Car constructor that takes a string name as argument. so, the compiler wont put the default constructor in the code. now, if you try to do: Car obj = new Car(); you will get an error because this constructor is not defined.
Is Java always provides a default constructor to a class?
Correct. If you omit a constructor, Java will assume that an empty one exists. Given the following code for a class: class MyClass { } You can make a call to the default constructor: MyClass mc = new MyClass(); Just keep in mind that the default constructor "goes away" if you implement another constructor. class MyClass { public MyClass(String str){ } } This line will now result in a "cannot find symbol" compiler error: MyClass mc = new MyClass();
What is the difference between default constructor and parameterized constructor?
A default constructor is one that has no parameters (C++ also calls constructors with all default parameters a default constructor), while a parameterized constructor is one that has at least one parameter without a default value. Default constructors can be provided by the compiler if no other constructors are defined for that class or any class the class inherits from, while parameterized constructors must always be defined by the developer.
Can Explain with an example to the default constructor?
The following example shows a Lamborghini class with two constructors: class Lamborghini { Lamborghini() { } Lamborghini(String name) { } } Will the compiler put in a default constructor for the class above? "No!" What about for the following variation of the class? class Lamborghini { Lamborghini(String name) { } } Now will the compiler insert a default constructor? "No Again!" What about this class? class Lamborghini { } Now we're talking. The compiler will generate a default constructor for the preceding class, because the class doesn't have any constructors defined. OK, what about this one below? class Lamborghini { void Lamborghini() { } } You might be tempted to say that, the compiler won't create one, since there already is a constructor in the Lamborghini class? Take another look at the Lamborghini class. What's wrong with the Lamborghini() constructor? It isn't a constructor at all! It's simply a method that happens to have the same name as the class. Remember, the return type is a dead straight way to tell us that we're looking at a method, and not a constructor. So, here again the compiler will put the default no-arg constructor in the class.
What is the method of constructor overloading?
The first thing to note about constructor overloading is that Java creates a no argument constructor for you if and only if you have not typed a constructor yourself. Every class has a constructor even abstract ones (default no argument constructor). Abstract constructors are always executed. To overload a constructor you can do the following: class Test { String name; Test(String n) { name = n; System.out.println("Constructing Test Object named: " + name); } } In the case above we are overloading the default no argument constructor with a constructor that takes a String parameter. You can write you own no argument constructor as follows: class Test { Test() { System.out.println("Constructing Test Object"); } } To override our own no argument constructor we do this: class Test { Test() { // our no argument constructor System.out.println("Constructing Test Object"); } String name; Test(String n) { // overloading our no argument constructor with this // constructor that take a String parameter name = n; System.out.println("Constructing Test Object named: " + name); } }
