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Answered 2012-04-07 19:21:35

The first thing to note about constructor overloading is that Java creates a no argument constructor for you if and only if you have not typed a constructor yourself. Every class has a constructor even abstract ones (default no argument constructor). Abstract constructors are always executed.

To overload a constructor you can do the following:

class Test {

String name;

Test(String n) {

name = n;

System.out.println("Constructing Test Object named: " + name);

}

}

In the case above we are overloading the default no argument constructor with a constructor that takes a String parameter.

You can write you own no argument constructor as follows:

class Test {

Test() {

System.out.println("Constructing Test Object");

}

}

To override our own no argument constructor we do this:

class Test {

Test() { // our no argument constructor

System.out.println("Constructing Test Object");

}

String name;

Test(String n) { // overloading our no argument constructor with this

// constructor that take a String parameter

name = n;

System.out.println("Constructing Test Object named: " + name);

}

}

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Related Questions


really there is no difference between constructor overloading and metho overloading


yes,because in constructor overloading constructor have same and different parameter list. In method overloading method have same name and different parameter list.



A constructor is just a special form of a method. You can overload constructors in the exact same way as you can overload any other method.


I think constructor overloading is the concept of polymorphism.


When we are initializing our object with different internal state then we can use the constructor overloading.


Overloading constructor means when you have multiple constructors in a class but with different number of arguments. We cannot override a constructor, but we can override a method having same arguments and same return type. This means when I subclass a particular class then I can call the superclass's class method and override that with subclass's own logic.


Constructor overloading, just like any function's overloading, is where more than one configuration of parameters exists for the function. Based on the number and type of the parameters, different versions of the function can be resolved by the linker. This is typically used in the constructor as the default constructor (no parameters), the copy constructor (one reference parameter of the same type as the class), and the conversion constructor (any other combination of parameters).


Yes. Method Overloading is a form of Polymorphism


method overloading means function having same name but different prototype .. e.g class demo { int i; public void display() { System.out.println("hello"); } public void display(int x) //method overloading { i=x; System.out.println("i="+i); } } class mainDemo { public static void main(String s[]) { demo ob=new demo();//creating object ob.display(); ob.display(5); } }


A copy constructor usually refers to a constructor which takes an object, and returns a copy of that object. I can think of no way to overload the constructor without changing its functionality.


Overloading a constructor means typing in multiple versions of the constructor, each having a different argument list, like the following examples: class Car { Car() { } Car(String s) { } } The preceding Car class has two overloaded constructors, one that takes a string, and one with no arguments.


Overloading a constructor means typing in multiple versions of the constructor, each having a different argument list, like the following examples: class Car { Car() { } Car(String s) { } } The preceding Car class has two overloaded constructors, one that takes a string, and one with no arguments


The main method is the method called when the Java application is started The constructor is called whenever a new object is instantiated.


A constructor is a special method that gets executed when the object is created.


Constructor overloading is the feature by which we declare multiple constructors for a single class. Ex: let us say we want to create multiple constructor for a class Test Public class Test { Public Test() { //code } Public Test(int vals) { //code } Public Test(String val) { //code } }


Default Constructor will be called first . If you override Validate method , then validate method will be called .


No. If you do not write a constructor for you classes, the default Object constructor can still be used.


Overloading a constructor means typing in multiple versions of the constructor, each having a different argument list, like the following examples: class Car { Car() { } Car(String s) { } } The preceding Car class has two overloaded constructors, one that takes a string, and one with no arguments. Because there's no code in the no-arg version, it's actually identical to the default constructor the compiler supplies, but remember-since there's already a constructor in this class (the one that takes a string), the compiler won't supply a default constructor. If you want a no-arg constructor to overload the with-args version you already have, you're going to have to type it yourself, just as in the Car example. Overloading a constructor is typically used to provide alternate ways for clients to instantiate objects of your class.


The only similarity is that both constructor and function overloads are distinguished by their signature -- the number and type of their arguments. Functions differ in that they also have a return type, which is also part of the signature, whereas constructors have no return type, not even void.


this in java is a keyword that refers to the current object of the class. It is also used in constructor overloading when you want to invoke one constructor from another within the same class.


You overload a constructor by declaring two or more constructors in a class, each with different signatures. When no constructor is specified, a default constructor and a copy constructor are implied. Both can be overridden. The default constructor can also be overloaded if all arguments are given default values in the declaration. You can add as many construction overloads as required in order to initialise your class. If your class has many members to initialise, it may be helpful to use a structure and an overloaded constructor to accept the structure. For every constructor that has exactly one argument, there should also be an equivalent assignment operator overload. The copy constructor assignment overload is implied if not specified.


Overloading a constructor means typing in multiple versions of the constructor, each having a different argument list, like the following examples: class Car { Car() { } Car(String s) { } } The preceding Car class has two overloaded constructors, one that takes a string, and one with no arguments. Because there's no code in the no-arg version, it's actually identical to the default constructor the compiler supplies, but remember-since there's already a constructor in this class (the one that takes a string), the compiler won't supply a default constructor. If you want a no-arg constructor to overload the with-args version you already have, you're going to have to type it yourself, just as in the Car example. Overloading a constructor is typically used to provide alternate ways for clients to instantiate objects of your class. For example, if a client knows the Car name, they can pass that to a Car constructor that takes a string. But if they don't know the name, the client can call the no-arg constructor and that constructor can supply a default name.


You can have any number of constructors for a class. All we need to do is implement constructor overloading. Ex: let us say we want to create multiple constructor for a class Test Public class Test { Public Test() { //code } Public Test(int vals) { //code } Public Test(String val) { //code } }


To have options wherein we can create objects of a class with different sets of parameter (initial) values



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