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first we work out the Mr.
Mr= 80g
Then we find out the Mr of Oxygen in NH4NO3.
Mr of oxygen=48g
Then we do 40/80 which equals 0.5 then we multiply it by 100 and we get 50%
This is our Percentage by mass.
Wiki User
∙ 8y ago
The molar mass of NO2 is 46.01 g/mol. The molar mass of oxygen in NO2 is 32.00 g/mol. To find the percent by mass of oxygen in NO2, divide the molar mass of oxygen by the molar mass of NO2 and multiply by 100%. Therefore, the percent by mass of oxygen in NO2 is (32.00 g/mol / 46.01 g/mol) x 100% ≈ 69.6%.
Wiki User
∙ 11y agoThe formula given shows that each formula unit contain two nitrogen atoms (one in the ammonium ion and one in the nitrate ion). The gram formula mass of ammonium nitrate is 80.04 and the gram Atomic Mass of nitrogen is 14.0067. Therefore, the percent by mass of nitrogen in ammonium nitrate is:
100[(2)(14.0067)/80.04] or 35.00 %, to the justified number of significant digits. (A more precise gram formula mass of ammonium nitrate would justify more significant digits.)
Wiki User
∙ 9y ago1. Determine the molar mass of NH4NO3 by determining the molar mass of each element in the formula and then adding them together.
N: 2 x 14.534g/mol = 29.068g/mol
H: 4 x 1.008g/mol = 4.032g/mol
O: 3 x 15.999g/mol = 47.997g/mol
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Molar mass of NH4NO3 = 81.097g/mol
2. Divide the molar mass of each element by the molar mass of NH4NO3 and multiply the result times 100. This gives you the percent composition of each element in the compound.
N: (29.068g/mol)/(81.097g/mol) x 100 = 35.843%
H: (4.032g/mol)/(81.097) x 100 = 4.971%
O: (47.997g/mol)/(81.097g/mol) x 100 = 59.188%
Wiki User
∙ 11y agoN: 1(14)= 14
O: 2(16)= 32
14+32= 46
32/24x100= 70%
Wiki User
∙ 12y agoNH4NO3
N - 14.0 X 2 = 28
H4 - 1.0 X 4 = 4
O3 - 16.0 X 3 = 48
Total molecular mass = 80
48/80 = 60%
Wiki User
∙ 8y agoSodium bicarbonate contain 57,137 % oxygen.
Wiki User
∙ 7y agoThe percentage by mass of sodium (Na) in a formula unit of sodium hydrogen carbonate (NaHCO3) is 27,38 %.
Wiki User
∙ 6y agoThe percent by mass of oxygen in N2O4 is 69,56 %.
Wiki User
∙ 11y ago28 g N/80 g NH4NO3 *100
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What is the mass percent of oxygen in of N2O4?
The percent by mass of oxygen in N2O4 is 69,56 %.
The gram-formula mass of no2 is defined as the mass of?
The gram-formula mass of a compound is the sum of the atomic masses of all the atoms in a formula unit of the compound. For NO2, the gram-formula mass is calculated by adding the atomic mass of nitrogen (N) and two times the atomic mass of oxygen (O).
What is the mass percent of oxygen in SO2?
The mass percent of oxygen in SO2 is 50 %.
How many moles of molecules are in 25.5g of NO2?
Determine the molar mass of NO2 using the subscripts in the formula and the atomic weights in grams from the periodic table. 1 mole NO2 = (1 x 14.0067g N) + (2 x 15.9994g O) = 46.0055g NO2 Calculate the moles NO2 by dividing the given mass by the molar mass. 25.5g NO2 x (1mol NO2/46.0055g NO2) = 0.554mol NO2
What is the approximate percent by mass of oxygen in SO3?
The molar mass of SO3 is 80.06 g/mol, with oxygen contributing 48.00 g/mol, which is 60% of the total molar mass. Therefore, the approximate percent by mass of oxygen in SO3 is 60%.
What is the mass percent of oxygen in of N2O4?
The percent by mass of oxygen in N2O4 is 69,56 %.
How find percent compsotion of oxygen in Na2O?
To find the percent composition of oxygen in Na2O, first calculate the molar mass of Na2O (Sodium oxide) which is 61.98 g/mol. The molar mass of oxygen is 16 g/mol. Then, calculate the percent composition of oxygen in Na2O using the formula: (16 g/mol / 61.98 g/mol) * 100. This gives you the percent composition of oxygen in Na2O, which is approximately 25.8%.
What is the mass percent of oxygen in SO2?
The mass percent of oxygen in SO2 is 50 %.
How many moles of molecules are in 25.5g of NO2?
Determine the molar mass of NO2 using the subscripts in the formula and the atomic weights in grams from the periodic table. 1 mole NO2 = (1 x 14.0067g N) + (2 x 15.9994g O) = 46.0055g NO2 Calculate the moles NO2 by dividing the given mass by the molar mass. 25.5g NO2 x (1mol NO2/46.0055g NO2) = 0.554mol NO2
What mass of ozone could be produced from a car's exhaust if 4.00 g NO2 react in an excess of oxygen?
To calculate the mass of ozone produced, we need to first determine the balanced chemical equation for the reaction between NO2 and oxygen to form ozone. Then, we can calculate the molar mass of ozone and use stoichiometry to find the mass produced from 4.00 g of NO2.
The gram-formula mass of no2 is defined as the mass of?
The gram-formula mass of a compound is the sum of the atomic masses of all the atoms in a formula unit of the compound. For NO2, the gram-formula mass is calculated by adding the atomic mass of nitrogen (N) and two times the atomic mass of oxygen (O).
What is the mass percent of oxygen in estriol?
Estriol (C18H24O3) contain 16,644 % oxygen.
What does oxygen oxygen nitrogen make?
Oxygen and nitrogen will not directly chemically react with each other under normal conditions. They will typically stay as separate molecules in the air.
What is the approximate percent by mass of oxygen in SO3?
The molar mass of SO3 is 80.06 g/mol, with oxygen contributing 48.00 g/mol, which is 60% of the total molar mass. Therefore, the approximate percent by mass of oxygen in SO3 is 60%.
If 230 g sample of a compound contains 136.6 g of carbon 26.4 g of hydrogen and 31.8 g of nitrogen The rest is oxygen What is the mass percent of oxygen in the compound?
The mass of the elements that are not oxygen equals 194.8g. The mass of oxygen is 230g - 194.8g = 35.2g of oxygen. Mass percent of oxygen = 35.2g O/230g x 100 = 15% O
Why if sucrose is 51.5 percent oxygen by mass and only 6.4 percent hydrogen by mass is there twice as many hydrogen atoms than oxygen atoms?
The molecular formula of sucrose is C₁₂H₂₂O₁₁. From this formula, we can see that there are 12 hydrogen atoms and 11 oxygen atoms in sucrose. Despite oxygen accounting for 51.5% of the mass and hydrogen only 6.4%, the ratio of hydrogen atoms to oxygen atoms is determined by the molecular formula, not the mass percentages.
The percent of oxygen by mass in 0.370 kg trinitrotoluene?
To find the percent of oxygen by mass in trinitrotoluene (TNT), you need to know the molecular formula of TNT. TNT contains 30.4% oxygen by mass, so in 0.370 kg of TNT, the mass of oxygen would be 0.370 kg * 0.304 = 0.11248 kg. To convert this to a percentage, divide the mass of oxygen by the total mass of TNT (0.370 kg) and multiply by 100 to get 30.4%.
