The balanced chemical equation for the combustion of propane is:
C3H8 + 5O2 --> 3CO2 + 4H2O
C3H8 + O2 ---------> CO2 + H2O UNBALANCED C3H8 + 5O2 ---------> 3CO2 + 4H2O BALANCED
Propane ( C3H8 ) will burn completely when it combines with the oxygen (O2) in air to form carbon dioxide (CO2) and water (H2O). The equation looks like this: C3H8 + 5O2 ---> 3CO2 + 4H2O The heat generated in the exothermic reaction causes more and more propane to "break apart" and combine with oxygen in air to produce the end products carbon dioxide and water. This will continue until the concentration of propane in air falls below a "threshold" and not enough heat is generated to support the combustion of any remaining propane. There is enough oxygen in air in an open space to support the combustion of an extremely large volume of propane.
Study island answer: C3H8 + 5O2 3CO2 + 4H2O
There seems to be a typo in your question. In the balanced chemical formula for the combustion of propane: C3H8 + 5 O2 --> 3 CO2 + 4 H2O + energy the products are on the right side of the arrow: CO2, H2O, and energy
C3H8 + 5O2 = 3CO2 + 4H2O, so the coefficient for O2 is 5
If you mean the balanced reaction of the combustion of propane, it is: C3H8 + 5 O2 ---> 3 CO2 + 4 H2O
The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
The chemical equation is:C5H12 + 8 O2 = 5 CO2 + 6 H2O
This answer represents a balanced chemical equation for the combustion of propane (C3H8). When propane reacts with oxygen (O2), it produces carbon dioxide (CO2) and water (H2O).
2c4h10o + 13o2 -----> 8co2 + 10h2o
The reaction is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
C3H8 + O2 ---------> CO2 + H2O UNBALANCED C3H8 + 5O2 ---------> 3CO2 + 4H2O BALANCED
C3H8 + O2 ---------> CO2 + H2O UNBALANCED C3H8 + 5O2 ---------> 3CO2 + 4H2O BALANCED
A balanced* equation for the burning of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. *Note that the participial form of "balance" is required for proper grammar in this sentence.
C3h8 + 5o2 -> 3co2 + 4h2o
C3H8 is the chemical formula for a Alkane Hydrocarbon called Propane.It is highly flammable. It burns to form CO2 and H2O
Propane ( C3H8 ) will burn completely when it combines with the oxygen (O2) in air to form carbon dioxide (CO2) and water (H2O). The equation looks like this: C3H8 + 5O2 ---> 3CO2 + 4H2O The heat generated in the exothermic reaction causes more and more propane to "break apart" and combine with oxygen in air to produce the end products carbon dioxide and water. This will continue until the concentration of propane in air falls below a "threshold" and not enough heat is generated to support the combustion of any remaining propane. There is enough oxygen in air in an open space to support the combustion of an extremely large volume of propane.