Concentration is 150 gm solute per 850 mL solvent: 150 g solute per (150g + 850g =) 1000 g solution = 15% (m/m) CaCO3, since 850 mL is equal to (rounded) 850 grams.
However calcium carbonate is rather INsoluble (smaller than 0.15 g/100 mL, about 0.15%) so this answer is physically impossible to achieve.
If the question was mistyped and could have been 150 mg(= milligram, not gm = gram) per 850 mL, THEN the answer would have been 0.15 g per (850g + 0.15g =) 850 g solution which is (100%*0.15/850=) 0.018% CaCO3
If the scoops are the same size, 50 with 2 scoops and 100 with 4 scoops have the same concentration. 2/50 = 0.04 4/100 = 0.04 but 150 with 5 scoops has less concentration 5/150 = 0.0333
This concentration is min. 150 mmoles/L NaCl.
There is 500 ml of liquid and 70% of it is alcohol so 30% is water. .3x500 =150 so 150 ml of H2 O Note 30% = .3=3/10 and 3/10 x500=1500/10=150
Yes! i recommend about, 1-2 portions of the yogurt a day :D
The concentration of a solution is moles/volume. 2.943g of pure sulphuric acid H2S4 is approximately 15 moles, and 15/150 cm3 is 10.
Hard water typically refers to ground water which has higher concentrations of dissolved minerals. To harden water, you simply add the minerals, which are most commonly calcium and magnesium chlorides and sulfates until you get a total mineral concentration of around 150 parts per million.
If the scoops are the same size, 50 with 2 scoops and 100 with 4 scoops have the same concentration. 2/50 = 0.04 4/100 = 0.04 but 150 with 5 scoops has less concentration 5/150 = 0.0333
For a concentration of 0,6 g sugar/1000ml: 15 ml for 150 mL.
20 g/150 mL = 0.13 g/mL = 130 g/L
This concentration is min. 150 mmoles/L NaCl.
There is 500 ml of liquid and 70% of it is alcohol so 30% is water. .3x500 =150 so 150 ml of H2 O Note 30% = .3=3/10 and 3/10 x500=1500/10=150
Yes! i recommend about, 1-2 portions of the yogurt a day :D
The concentration of a solution is moles/volume. 2.943g of pure sulphuric acid H2S4 is approximately 15 moles, and 15/150 cm3 is 10.
The best way to lower calcium hardness in the pool water is to drain the water and refill with water of lower calcium hardness. Have the calcium hardness tested for both the pool water and fill water. Ideal range is 175-300ppm. There are 'calcium reducer' products available through pool stores, but not sure how effective or economical they are.
By the addition of washing soda (sodium carbonate)Calcium and magnesium ions present in hard water react with sodium carbonate to produce insoluble carbonates. The water now contains soluble and harmless sodium salts.Calgon processCalgon is a trade name of a complex salt, sodium hexametaphosphate (NaPO3)6. It is used for softening hard water. Calgon ionizes to give a complex anion:The addition of Calgon to hard water causes the calcium and magnesium ions of hard water to displace sodium ions from the anion of Calgon.This results in the removal of calcium and magnesium ions from hard water in the form of a complex with Calgon. The water is softened and sodium ions are released into water.By the ion-exchange process (Permutit process)Permutit or sodium aluminum silicate is a complex chemical compound, which occurs as a natural mineral called Zeolite. Permutit or zeolites are insoluble in water and have the property of exchanging ions present in them with the ions present in the solution. Permutit or zeolites are packed in a suitable container and a slow stream of hard water is passed through this material. As a result, calcium and magnesium ions present in hard water are exchanged with sodium ions in the permutit (Na+Al-Silicate). The outgoing water contains sodium salts, which do not cause hardness.
150 milliliters of pure water weigh 150 grams.
We must first figure out the amount of NaCl in moles: M = mol/L = mmol/mL 6 = mmol/25 mL 150 mmol NaCl Now divide by the total volume to get the final concentration: 150 mmol/100 mL = 1.5 M NaCl