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You can test a capacitor using a multimeter and two leads by placing the multimeter in ohms mode. It works best with a needle type meter, not a digital meter. Connect the leads to the capacitor and you will notice that the resistance pulses down, and then settles out at infinity. Reverse the leads, and you will notice the same effect, except that the pulse will be larger because the capacitor got charged in the opposite direction. Go back and forth. This won't be apparent for very small capacitors because the pulse is too short. Also, for electrolytic capacitors, they should only be charged in one direction, so you should start by discharging the capacitor and then connecting it in only one direction. Do not reverse the leads in this case. Just discharge and try again to see the effect. Try this for various capacitors. You will notice that the pulse duration is larger for larger capacitance.
Gain in a CE configuration of a BJT is collector resistance divided by emitter resistance, subject to the limit of hFe. The emitter bypass capacitor will have lower impedance at high frequency, so the gain will be higher at higher frequency, making this a high-pass amplifier.
The differential equation for a capacitor is dv/dt = i/c. Set that up in a circuit and force an AC power source, such as sin(theta), and you will see that lowering the frequency will increase the equivalent resistance. I'll leave that exercise for you. The net result is that a series capacitor is a high-pass filter, while a parallel capacitor is a low-pass filter.
when ever current passing through any two parallel transmission line than due to the dieletric property of conductor some what capacitance effect will be generate between them that phenomina called as capitance reactance/////////////////// that symply we can called capitance reactance is measure of capitance The reactance of a capacitor is its resistance.
The dielectric material between the plates.
If the resistance is in series with the capacitor, the charge/discharge time is extended.
The effective resistance of the capacitor reduces the ripple current through the capacitor making it less effective in its function of smoothing the voltage. But if the capacitor filter is fed by a transformer and diodes, the resistance of the transformer exceeds that of the capacitor.
In case of a lossy capacitor, its series equivalent resistance will be large.
The capacitive effect is an element's opposition to a change in AC voltage. The resistor will develop a positively charged current at it flows through a capacitor. This will prevent a change in the initial voltage.
You can test a capacitor using a multimeter and two leads by placing the multimeter in ohms mode. It works best with a needle type meter, not a digital meter. Connect the leads to the capacitor and you will notice that the resistance pulses down, and then settles out at infinity. Reverse the leads, and you will notice the same effect, except that the pulse will be larger because the capacitor got charged in the opposite direction. Go back and forth. This won't be apparent for very small capacitors because the pulse is too short. Also, for electrolytic capacitors, they should only be charged in one direction, so you should start by discharging the capacitor and then connecting it in only one direction. Do not reverse the leads in this case. Just discharge and try again to see the effect. Try this for various capacitors. You will notice that the pulse duration is larger for larger capacitance.
Gain in a CE configuration of a BJT is collector resistance divided by emitter resistance, subject to the limit of hFe. The emitter bypass capacitor will have lower impedance at high frequency, so the gain will be higher at higher frequency, making this a high-pass amplifier.
The differential equation for a capacitor is dv/dt = i/c. Set that up in a circuit and force an AC power source, such as sin(theta), and you will see that lowering the frequency will increase the equivalent resistance. I'll leave that exercise for you. The net result is that a series capacitor is a high-pass filter, while a parallel capacitor is a low-pass filter.
when ever current passing through any two parallel transmission line than due to the dieletric property of conductor some what capacitance effect will be generate between them that phenomina called as capitance reactance/////////////////// that symply we can called capitance reactance is measure of capitance The reactance of a capacitor is its resistance.
Does a magnetic field have an effect on a capacitor when it is placed between the plates? Yes, a magnetic field between the plates of a capacitor would have some effect. Without more information it is difficult to determine how much.
A capacitor try to leads the current while a inductor tries to legs the current so they cancels each other's effect ....
by using capacitor
Any circuit using a capacitor will not work if the cap is short-circuited.