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What else can I help you with?
Find the energy of a photon whose frequency is 5x10 12 Hz?
The energy of a photon can be calculated using the formula E = h * f, where h is Planck's constant (6.626 x 10^-34 J*s) and f is the frequency of the photon. Thus, for a frequency of 5 x 10^12 Hz, the energy of the photon would be 3.31 x 10^-21 Joules.
What is the wavelength of a photon whose energy is twice that of a photon with a 580 nm wavelength?
Since the energy of a photon is inversely proportional to its wavelength, for a photon with double the energy of a 580 nm photon, its wavelength would be half that of the 580 nm photon. Therefore, the wavelength of the photon with twice the energy would be 290 nm.
What is the wavelength of a photon that has three times as much energy as that of a photon whose wavelength is 779 nm?
Photon energy is proportional to frequency ==> inversely proportional to wavelength.3 times the energy ==> 1/3 times the wavelength = 779/3 = 2592/3 nm
What is the energy of a photon that has a frequency of 5.0 1014 hz?
The energy of a photon can be calculated using the relationship E = hf where h is Planck's constant 6.626 x 10^-34 m^3 kg /s and f is the frequency in s^-1 (Hz). The energy of this photon is 3.13 x 10^-31 J.
How can an atom of size 1angstrom can absorb a photon of 5000 wavelength?
I presume you asking, "How can an atom of size about 1 angstrom absorb a photon whose wavelength is 5000 angstroms? Wouldn't the photon be too large for that atom?" The paradox is resolved in this way: the instant you start to discuss electro-magnetic radiation as a photon instead of a transverse electro-magnetic wave, then you negate the wave-length aspect of the light. Instead, you view light as a collection of photons -- particles whose "size" (if that word has meaning) is point-like -- with a specific energy instead of specific wavelength. A photon is NOT a snake-like wave, vibrating like a rubber band, with a length at least that of its wave-length, as it moves through a medium. A photon is a point particle with a specific energy. You can describe light as a EM wave with a wave-length OR as a collection of point particles. You can NOT do both at the same time. Light exhibits the characteristics of one OR the other, but NEVER both.
What is a particle of relatively negligible mass?
A photon is a particle with negligible mass, whose energy and momentum are determined by its frequency and wavelength. It is a fundamental particle that carries electromagnetic radiation.
Electromagnetic waves with a longer wavelength has?
An electromagnetic wave with a longer wavelength will have a smaller frequency, and less energy per photon.An electromagnetic wave with a longer wavelength will have a smaller frequency, and less energy per photon.An electromagnetic wave with a longer wavelength will have a smaller frequency, and less energy per photon.An electromagnetic wave with a longer wavelength will have a smaller frequency, and less energy per photon.
What is the vibration whose frequency is a multiple of the fundamental frequency?
Overtone
What is the frequency of a photon whose wavelength is 6000 Armstrong's?
The frequency of a photon with a wavelength of 6000 Ångströms can be calculated using the formula: frequency = speed of light / wavelength. For this case, the speed of light is approximately 3.00 x 10^8 m/s. Converting the wavelength to meters, we get 6.00 x 10^-7 m. Plugging these values into the formula, we find the frequency to be approximately 5.00 x 10^14 Hz.
Why you convert FM signal to IF frequency?
Mix it with a local oscillator whose frequency is (the IF frequency) away from the frequency of the FM signal you're interested in.
What is the frequency of a wave whose wavelength is 5 cycle and whose frequency is 5Hz?
The answer is in the question! 5 Hz Also, a wavelength cannot be 5 cycles - wrong units.
What is the energy associated with a photon whose wavelength is 600 NM?
The energy of a photon is given by E = hc/λ, where h is the Planck constant, c is the speed of light, and λ is the wavelength. Plugging in the values gives E = (6.63 x 10^-34 J s * 3 x 10^8 m/s) / (600 x 10^-9 m) = 3.31 x 10^-19 J.
