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What is the energy of a photon that has a frequency of 5.0 1014 hz?
Wiki User
∙ 13y ago
The energy of a photon can be calculated using the relationship E = hf where h is Planck's constant 6.626 x 10^-34 m^3 kg /s and f is the frequency in s^-1 (Hz). The energy of this photon is 3.13 x 10^-31 J.
Wiki User
∙ 9y ago
Wiki User
∙ 13y agoHere is your equation: E=hf where h is "Planck's constant" (6.626 x 10^-34 J x sec) and f is the frequency.
E=hf
E=(6.626 x 10^-34 J x sec) x (4.8 x 10^15 Hz)
E=3.2 x 10-18 J
Wiki User
∙ 13y agoIf I counted correctly (and I probabely didn't) your asking the energy of a photon whose frequency is 5.8*10^40 (a much neater convention).
Its a simple problem. E=hf
h=6.6*10^(-34)
So E=(6.6*10^(-34))(5.8*10^40)
I'll let you work it out for yourself.
Wiki User
∙ 13y agoThe energy of a photon is given by the relation
E = hf
In this equation, h is called "Planck's constant" and has a value of 6.26 x 10^-34 Joules*sec. The frequency of the photon is f, and therefore the energy of the photon follows directly from this relation. The energy of a photon whose frequency is 5.0 * 10^14 Hz is
E = (6.26 * 10^-34 Joules*sec) * (5.0 * 10^14 Hz)= 3.13 * 10 ^-19 Joules
In particle physics, which deals with numbers on a much smaller scale than classical physics, the units of "electron-volts (eV)" are used. One electron-volt is the energy that an electron gains after traveling from a point in space to another point in space which is 1 Volt higher. Or as a physicist would say, "An electron-volt is the energy obtained by an electron after traveling through a 1 volt potential difference of an electric field."
Since a photon is a particle and belongs to the realm of particle physics, its energy is best described in terms of electron-volts, in which case
1 electron-Volt = 1eV = 1.602 *10^-19 Joules
And
E = hf = 3.13 * 10^-19 Joules = 1.95 eV
Wiki User
∙ 13y agoThe energy of a photon whose frequency is 5.8 x 1014 Hz is: 2.4322643592E-11 electron volts.
Wiki User
∙ 11y agoPhoton energy = (Planck's Konstant) x (frequency) =
(6.63 x 10-34 joule-second) x (5 x 1014 per second) = 3.315 x 10-19 joule
Wiki User
∙ 11y agoE=5.8*10^14*6.626*10^-34=3.84*10^-19
Wiki User
∙ 8y agoThe energy is 2,3160 eV.
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