140 cc = 70 g powder
H2 (g) + FeSO4 (s) hydrogen gas and iron sulphate
The answer is NOT a)a) I(g) + e → I-(g)b) I2(g) → 2I(g)c) I(g) → I+(g) + ed) Na(g) + I(g) → NaI(s)e) Na(s) + 1/2I2(s) → NaI(s)
a) I(g) + e → I-(g)b) I2(g) → 2I(g) c) I(g) → I+(g) + ed) Na(g) + I(g) → NaI(s)e) Na(s) + 1/2I2(s) → NaI(s)The correct answer out of these choices is clearly a) I(g) + e → I-(g). That is the right answer.
50% citric acid powder = 50 g citric acid/100 g 4% citric acid solution = 4 g citric acid/100 ml distilled water Determining how much citric acid powder to use is based upon how much citric acid solution you wish to make. To make 100 ml of solution, you should use 8 g of powder.
80 g of cocoa powder is equal to one cup. It is also equivalent to 3 oz.'s or about 5 tablespoons.
140 cc = 70 g powder
Do you mean iron powder mixed with sulphur powder? Fe(s) + S(s) ---> FeS (iron sulfide)
It depends a bit on how well compacted the powder is but a common number for uncompacted powder would be 0.8 g/cm³.
L. G. Berry has written: 'Mineralogy : concepts, descriptions, determinations' -- subject(s): Mineralogy 'X-ray powder data for ore minerals' -- subject(s): Determinative Mineralogy, Mineralogy, Tables 'Mineralogy' -- subject(s): Lending library, Mineralogy
H2 (g) + FeSO4 (s) hydrogen gas and iron sulphate
Gish s gs g s gs g s gs g s gs g s g
You need sand and gunpowder, crafted like this: S G S G S G S G S S = Sand G = Gunpowder
http://wiki.answers.com/Q/100_g_of_powder_is_36.00_than_what_will_be_the_cost_of_12_g"
when bleaching powder reacts with ammonia, nitrogen gas is evolved along with calcium chloride and water. The balanced reaction is: 3CaCl(OCl)(s)+2NH3(aq) = 3CaCl2(aq)+N2(g)+3H2O(l)
K2CO3 (s) → K2O (s) + CO2 (g)2SO3 (g) → 2SO2 (g) + O2 (g) CaCO3 (s) → CaO (s) + O2 (g)
gun powder