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1. NAND gate is used to invert the input A (by connecting A to both inputs). 2. NAND gate used to invert B the same way 3. Now put A' and B' into into a third NAND gate. The output will be (A'B')' which is equivalent to A+B.
NOR gate = not(A or B) = A nor BAND gate = A and BAND gate = not(not A or not B)AND gate = not(not(A or A) or not(B or B))AND gate = (A nor A) nor (B nor B)Therefore using 2 input NORs to make a 2 input AND you need three NORs. If you wanted something different (e.g. a 5 input AND) the above proof can be modified appropriately to get your answer.
pass the inputs through an nand gate and again pass them through inverter,which is again formed by an nand gate
nand gate
ans. 3 nand gates resoon :- OR GATE :- x+y NAND GATE :- x'+y' LOGIC :-so the logic is is we apply NAND to the inputs x' and y' instead of xand y we would get x+y DESIGN PROCEDURE 1. for inverting the input x and y can be done by NAND gates , 2. take a NAND gate and pass both x in both the inputs it means x NAND x gives you x' 3. follow similar procedure for inverting y 4. and then all the outputs of those NAND gates as the inputs of another NAND gate
A 2 input NAND gate requires 4 NOR gates.A 3 input NAND gate requires 5 NOR gates.A 4 input NAND gate requires 6 NOR gates.etc.
When the two input terminals of a NAND gate are short circuited, it acts as a NOT gate.
NOT Gate
Connect both inputs of the NAND gate together to form a single input. Tie one input of the NAND gate to a logic high (Vcc) and connect the other input to the desired input signal.
A: NAND implies not and to be true both input must be hi or true <> There are two flavors of NAND gate. The positive input/negative output NAND will have a low output if and only if both inputs are high. The negative input/positive output NAND will have a high output if and only if both inputs are low.
The 7400, and its variations, is a quad two input NAND gate.
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the not gate applied to and gate is nand gate
There are two forms of the NAND gate. Inverted input: Ouput = not Input1 and not Input2 and not Input3 ... Inverted output: Output = not (Input1 and Input2 and Input3 ...)
The 7400, and its variations, is a quad two input NAND gate.
1. NAND gate is used to invert the input A (by connecting A to both inputs). 2. NAND gate used to invert B the same way 3. Now put A' and B' into into a third NAND gate. The output will be (A'B')' which is equivalent to A+B.
The 74LS00 is a quad two input NAND gate with low power schottkey TTL implementation.