byte ptr is an assembler directive that says the following operand is an address of a byte.
/** * Return the byte of DHCP option data. * * @param client DHCP client. * @param ptr pointer obtained by dhcp_get_option_ptr(). * * @return byte value at the given address. */ static u8_t dhcp_get_option_byte(u8_t *ptr) { LWIP_DEBUGF(DHCP_DEBUG, ("option byte value=%"U16_F"\n", (u16_t)(*ptr))); return *ptr; } #if 0 /** * Return the 16-bit value of DHCP option data. * * @param client DHCP client. * @param ptr pointer obtained by dhcp_get_option_ptr(). * * @return byte value at the given address. */ static u16_t dhcp_get_option_short(u8_t *ptr) { u16_t value; value = *ptr++ << 8; value |= *ptr; LWIP_DEBUGF(DHCP_DEBUG, ("option short value=%"U16_F"\n", value)); return value; } #endif /** * Return the 32-bit value of DHCP option data. * * @param client DHCP client. * @param ptr pointer obtained by dhcp_get_option_ptr(). * * @return byte value at the given address. */ static u32_t dhcp_get_option_long(u8_t *ptr) { u32_t value; value = (u32_t)(*ptr++) << 24; value |= (u32_t)(*ptr++) << 16; value |= (u32_t)(*ptr++) << 8; value |= (u32_t)(*ptr++); LWIP_DEBUGF(DHCP_DEBUG, ("option long value=%"U32_F"\n", value)); return value; } #endif
In 8086 the instruction queue is 6 byte long. This is because even the longest 8086 instruction is 6 byte long. Thus it is possible to prefetch even the longest instruction in the instruction set.
in 8086, there is instruction queue of 6 byte. It is one of the reason behind giving name. 8086 was introducing pipeline architecture.
8086 is a small 4 or 6 byte instruction cache or queue that perfetched a few instructions before they were executed. In addition, the 8086 addressed 1M byte of memory, which is 16 times more than 8085. N.K.Jha narayankumarjha2010@gmail.com
pata nai
8086 has 20 address lines. Therefore it can address 220 bits or 1,048,576 bits of memory, or roughly 1 MB (mega byte).
// Return true if str is a palindrome bool is_palindrome (char* str) { int len; char* cpy; char* ptr; bool b; len = strlen (str); if (!len) return false; cpy = malloc (sizeof(char) * (len + 1)); ptr = cpy; while (*ptr=*str) { if (*ptr>='A' *ptr<='Z') *ptr+=('a'-'A'); if ((*ptr>='a' && *ptr<='z') (*ptr>='0' && *ptr<='9')) { ++ptr; } ++str; } *ptr = '\0'; --ptr; str = cpy; while ((cpy!=ptr) && (cpy!=(ptr+1)) && (*cpy==*ptr)) { ++cpy; --ptr; } b = (*cpy==*ptr); free (str); return b; }
Because the 8086 is a 16 bit processor. Memory is organized as 512 MW of memory, or 1024 MB of memory.
The BHE (Bus High Enable) pin on the 8086 is latched by the 8282 in order to indicate if a write cycle is a word (BHE=1) or byte (BHE=0) cycle.
byte
BHE is used to enable the high order bus so as to differentiate between a word operation and a byte operation.
A function that calls itself. Example: ProcessList (list *ptr) { if (ptr!=NULL) { DoSomething (ptr->data); ProcessList (ptr->next); } }