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There are 7 horses and 21 people. 7 horses would equal 28 legs and 21 people would equal 42 legs which all together would equal 70 legs. By the same token, there could also be 17 horses and 1 man, 16 horses and 3 men, etc. For a brain teaser if you want a definitive answer you must have left out a piece of information like maybe the ratio of men to horses. If there was originally one man for each horse and then half of the men left, you can solve it with the following formula: There were originally x number of men and x number of horses. Now there are 1/2 x number of men. So, there are 2(1/2 x) men's legs and 4 x horses' legs. 2 (1/2 x) + 4x = 70 x + 4x = 70 5x = 70 x = 14 There are now 14 horses (56 legs) and 7 men (14 legs).
Horses are quadrupeds, so they have 4 legs.
If they were all horses you'd have 440 legs, so you're 184 legs "short", so you have half that number of chickens ie 92, leaving 18 horses. That's 92 x 2 and 18 x 4 legs, 184 + 72 = 256
horses.....
Yes. A "quadruped" (Latin having four feet) is any animal with four legs.
All horses have the chestnuts on the inside of the legs.
If all were horses there would be 428 legs. The shortfall of 36 legs represents 18 chickens so there are 89 horses.
Horses are mammals/animals with four legs.
The length of the horses legs will vary according to the horses overall height.
Answer : 33 horses. Number of Horses (H) + Number of Chickens (C) = 45 therefore C = 45 - H There are 4H horse legs and 2C chicken legs so, 4H + 2C = 156 substituting for C gives :- 4H + 2(45 - H) = 156 4H + 90 - 2H = 156 2H = 156 - 90 = 66 H = 33 There are 33 horses (and 45 - 33 = 12 chickens)
28 horses multiplied by 4 legs each horse equal 112 legs 28 * 4 = 112
You are supposed to: 1) Write two equations, one for the number of heads (express it in terms of the number of cows and horses, which of course are expressed as variables), and one for the number of legs (also expressed as an equation in terms of the number of cows and horses. 2) Solve the two equations simultaneously.