Void means there is no data type. So if you have a void function it does not return a value (and attempting to do so will cause an error) whereas a non-void function (ex. int, long, String, bool, etc) will return a value of that type.
Strictly speaking a void routine is not a function, since a function must return a value. Therefore, a void routine is a subroutine that does not return a value as its name, and can be called standalone.
For example, a void routine to add two numbers together and place the value in a third could be called as:
void Sum (int one, int two, int * three) ;
and could be called as:
Sum (firstVal, secondVal, &thirdVal) ;
Void has two purposes: when used as the formal return value of a function, it simply means that the function returns no value, not even zero. But when used to specify a void pointer type (void*), it simply means that the pointer is of unknown type. It is up to the caller to decide the actual type. However C++ is more strict than C with regards to type-safety, thus the return value of the C-style malloc function must be explicitly cast to the appropriate type. In C, the return value need not be explicitly cast, which could lead to errors if you later cast the void pointer to the wrong type.
void means nothing and it does exactly that.. for example...
the function declaration:
void function_name(int)
tells c compiler that the user defined function named function_name will take an integer as an argument and after completion of task would return nothing...
void means that the function you are trying to use or/and define does not return arguments.
A void function is simply a function that returns no value.
There is no such thing as devoid in C++.
Call by reference means calling a function using a reference to a variable or a pointer. You call a function by passing refrences to a variable. For eg: void x(int &a) { a=2; } void main() { int s=3; x(s); } OR void a(int &c) { c=5;}void main(){ int *p; *p=2a(*p);}
void foo (char& c) { cin >> c; } int main() { char ch[10] {}; for (size_t c=0; c!=10; ++c) foo (c[0]); }
There is no such term in C++. You probably meant void datatype. Void simply means "no type" and is primarily used as a place-holder for functions that do not return a value, since all functions must return something even when they return nothing at all. Not to be confused with void* which is a pointer to any type which, if non-null, must be cast to the correct type before being dereferenced.
No. There is no default return type for functions, it must be explicitly specified in both the function declaration and in the definition. To specify no return value, return void. To return a variant type, return void* (pointer to void). Otherwise return the exact type.
It doesn't. Void has the same meaning in both.
There is no such thing as devoid in C++.
doesn't return the value.
void main() { int *x = malloc(sizeof(int) * 10); }
#include int main (void) { puts ("1 2 3"); }
Call by reference means calling a function using a reference to a variable or a pointer. You call a function by passing refrences to a variable. For eg: void x(int &a) { a=2; } void main() { int s=3; x(s); } OR void a(int &c) { c=5;}void main(){ int *p; *p=2a(*p);}
int main (void) { puts ("Hello, world"); return 0; }
void myfun (int *pi){if (i==NULL) printf ("check failed");}
Example: int main (void) { LOOP: goto LOOP; }
void swap(int& a, int& b ) { a^=b^=a^=b; }
By returning a value. Or using type 'void'.
For example: int main (void) { return 0; }