Static in C/C++ means that the variable will keep its value across calls to the function.
ex:
func() {
static int x=0;
++x;
cout << x << endl;
}
main() {
func();
func();
func();
}
This will print:
1
2
3
*NOT*
1
1
1
println is not a C++ keyword.
Static binding occurs at compile time. Dynamic binding occurs at runtime.
AUTO EXTERN STATIC are the storage classes in c++
In C there are functions only, In Java methodsonly (static methods as well), in C++ both.
#include <stdio.h> static int myvar1, myvar2; int main (void) { puts ("It was easy"); return 0; }
Yes and no. Static vs dynamic binding is not a C or C++ language issue; it is a linker issue. If you link with a .lib file that contains stubs for run-time loading, then the called routine will not be loaded until it is invoked, and it will not be made a part of the load module.
If you mean the original name of C++, it was originally called "C with Classes". However, after the introduction of template metaprogramming, it was renamed C++ which meant "the successor to C".
Static member variables are local to the class. That is, there is only one instance of a static member variable, regardless of how many objects are instantiated from the class. As such, they must be declared inside the class, and defined outside of the class.
Nothing. I guess you mean a static variable.
'int' is one of the built-in data-types, it is meant to hold integer values.
Yes, but overloads cannot differ by return type alone. The signatures must differ by the number and/or the type of the arguments.
The C++ standard has this to say about dynamic initialisation:"Objects with static storage duration shall be zero-initialised before any other initialisation takes place. Zero-initialisation and initialisation with a constant expression are collectively called static initialisation; all other initialisation is dynamic initialisation."