Velocity diagrams are drawn perpendicular to the link ....whereas acceleration diagrams are drawn by knowing the values 2 components radial or centripetal component and tangential component.......the radial component moves parallel to the link and perpendicular to the velocity diagram.....but the tangential component moves perpendicular to the link and parallel to the velocity diagram .
1285.19 mph
The height of a wind turbine has no impact on the turbine's output wattage. The factors that effect the watts produced are: * The efficiency of turbine design (this is at most 59%) * the density of the air * the radius of the turbine (that is, the length of each fin) * the velocity of the wind passing through the turbine An 80 ft tall turbine would presumably have a fin length (that is, turbine radius) of at most 30 ft. Thus, at sea level on a 59 degree (F) day, in an 8 m/s (18mi/h) wind, with the most efficient turbine design possible, you would generate approximately 15.4 Kilowatts. See: http://en.wikipedia.org/wiki/Wind_turbine#Potential_turbine_power
The turbine converts pressure & heat energy (in steam turbine & gas turbine), velocity energy (in hydro turbine) into mechanical energy which produces rotation of the turbine. This mechanical force is used to rotate the rotor(which is coupled with the same shaft as that of turbine) of the generator which converts this mechanical energy into electrical energy.
It is an engine.A steam turbine is a heat engine that uses the expansion of steam passing through stationary nozzles and blades on a shaft to turn the shaft. The steam can move through the turbine axially (one end of shaft to the other end), radially (shaft to outer casing), or tangentially (around the outer edges of the turbine wheel). In an impulse turbine, the steam is expanded in nozzles and pushes the blades. In a reaction turbine the steam is expanded in the nozzles AND in the blades, the reaction of the expansion of the steam pushes away from the blades spinning the wheel in the process. The expansion of the steam is necessary to increase its velocity through the turbine.
When flow of water on turbine is tangential, flow is tangential flow
Tangential velocity is equal to (mass x velocity^2)/radial distance
Vt=w*r where; * is multiply Vt is tangential velocity w is omega(angular mometum) r is radius
Yes. Imagine a ball on a rigid pole being swung around, and slowing down. It's tangential velocity is positive but it's tangential acceleration is negative
the tangential velocity is equal to the angular velocity multiplied by the radius the tangential velocity is equal to the angular velocity multiplied by the radius
parallel to the surface of the Earth
the peripheral velocity of the turbine is the around velocity. the increase in the velocity of the peripheral will decrease the velocity of the flow towards the turbine
The tangential velocity is greater as the radius of the point on the rotating object increases. For a rotating object v = rw Where v is the tangential velocity r is the radius of the point And "w" is omega or angular velocity (in radians per second)
No. If you can drive around a ten-mile track in the same time it takes you to drive around a one-mile track, then your angular velocity is the same in both cases. But in order to do that, you'll need much higher tangential velocity during the longer run. Tangential velocity is what you'd normally call your 'speed' as you blaze around the track.
Because there is no tangential force acting on the object in uniform circular motion. The proof that there is no tangential component of acceleration is the fact that the tangential component of velocity is constant.
Tangential velocity squared is GMs/r and velocity v =29814m/s and the centripetal acceleration is v2/r= 5.928 E-3 m/s2
Whirl velocity of a turbine is determined by how fast the turbine can turn when it is moving. This is a factor considered with airplane manufacturing. Whirl velocity is the number of times in a second that a turbine can rotate, moving at a given speed.