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What is the value of g when Equator moves towards pole?
The value of acceleration due to gravity (g) decreases as you move from the Equator towards the poles due to the centrifugal force caused by the Earth's rotation. At the Equator, this force counteracts some of the gravitational force, resulting in a lower g value compared to the poles.
Is the maximum value g at equator?
Yes, the maximum value of acceleration due to gravity (g) is at the equator because the centrifugal force due to the Earth's rotation reduces the effective gravitational force. This results in a maximum g value at the equator compared to other latitudes.
Is there any difference between the value of g at the equator and the poles?
Yes, there is a difference in the value of acceleration due to gravity (g) at the equator and the poles. This is because the Earth is not a perfect sphere and has an oblate shape. At the equator, the centrifugal force due to the Earth's rotation reduces the effective gravity and makes g slightly smaller compared to the poles where this effect is minimal.
Is centrifugal force is more at equator than poles?
No, centrifugal force is greater at the poles than at the equator because the Earth's rotation causes a bulging effect at the equator that counteracts the centrifugal force. This is why objects weigh slightly less at the equator compared to the poles.
What the time periods of a simple pendulum at equator of the earth?
The time period of a simple pendulum at the equator of the Earth is slightly longer than at other latitudes due to the centrifugal force from the Earth's rotation. This force decreases the gravitational force experienced by the pendulum, leading to a longer period. The difference in period between the equator and other latitudes is very small, however, and not easily noticeable in everyday practice.
Standing at the equator What is the centripetal force you experience due to the rotation of the earth How much does this force compare to the gravitational force you experience would it be noticeabl?
say your mass (m) is 100 kgvelocity (v) at equator = 40 030 000 / 86164 = 464.6 metres / secearth radius(r) = 6 371 000 metresacceleration due to gravity at earths surface (g) = 9.82 (m/s)/s.gravity force at earth surface ( f = m * g) = 100 * 9.82 = 982 newtons.centripetal force at equator f = m * ((v^2)/r)f = 100 * ((464.6^2)/6 371 000)f = 3.39 newtons
Where is the strength of gravitatioal force in the poles or equator?
The bulging Earth has more surface "gravity" at its equator.
What is the force that dictates that objects weigh more at the equator than at the poles?
Well the above question is not true, The same object will weigh less at the equator than at the poles (of Earth). The force is the force of gravity and the effect is because the object placed at the poles will be nearer the center of the Earth than at the equator because the Earth is an Oblate Spheroid.
Why earth is not spherical in shape and why it bulges at equator?
Earth is an oblate spheroid due to its rotation causing a centrifugal force that pushes material outward at the equator. This bulging at the equator is a result of the Earth's rotation, the centrifugal force causes the equatorial region to push outward, counteracting gravity and giving the Earth a slightly flattened shape.
Explain why Geostrophic wind is not possible at the equator?
Geostrophic wind is not possible at the equator because the Coriolis force is negligible at the equator due to the Earth's rotation, resulting in a weak pressure gradient force dominating. This weak Coriolis force prevents the balance between pressure gradient force and Coriolis force required for geostrophic winds.
What causes earth flattening of the earth at two poles?
used by spinning motion of the earth around its axis passing through the poles...the force being max at the equator...since at tym of formation, earth was in fluid state, the force of cohesion was small & could not balance the centrifugal force...hence it bulged out at the equator
Where is the strengh of gravitational forcen in the poles or equator?
If the Earth were a (homogeneous) sphere, the gravitational force on its surface would be the same everywhere. I think that the gravitational force is slightly larger at the equator (center bulging Earth). But you might not measure it because of the rotation of the Earth.
