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What is the HCPCS or CPT Code for .9 percent sodium chloride irrigation solution 1000ml?
Wiki User
∙ 11y ago
A4217 sterile water saline
Wiki User
∙ 11y ago
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How do you prepare 0.1M iodine solution?
2grm iodine and 4grm KI add to 1000ml of water
How many moles of barium chloride are in 1.5 liter of a 0.256 molar solution?
.256 molar= 256 mols of solute per 1000ml of solution. Since there are 1000ml in 1L, there are 256 mols of BaCl2 for every liter. Multiply this by 1.5 and you get a total of 384 mols of BaCl2 in 1.5L of a .256 molar solution
How do you prepare 2N ammonium hydroxide solution from 25 percent ammonium solution?
Reference: the density of 25% NH4OH solution = 0.907g/cm³ Therefore 1 litre of solution has mass 907g 25% = 25/100*907 = 226.75g NH3 in 1 litre solution Molar mass NH3 = 17.031 g/mol 226.75g = 226.75/17.031 = 13.31N solution To make 1 litre of 2N solution: ( Work in ml= 1000ml) N1V1 = N2V2 13.31*V1 = 2*1000 V1 = 2000/13.31 V1 = 150.2ml Measure out 150.2ml of the 25% solution and dilute to 1 litre. This is a 2N solution.
Calculate the volume of solution needed to dissolve 0.25 moles NaCl to make a 3.0M solution?
3.00 M, or 3 moles per (L) "liter" calls for having 3 moles per liter of the solution. The question asks how many moles must be in 250ml of a solution that has 3 moles per Liter. You must ask yourself what percent of 1 Liter is 250mls? Since there are a thousand ml in one liter, (1000ml=1L), then 250ml is exactly 25% of a Liter, or .25L. So, 250ml can only hold 25% of the 3.00 Molarity. Meaning that you multiply 3 x .25 and get .75 moles.
25.0 ml of a 0.2450 m nh4cl solution is added to 55.5 ml of 0.1655 m fecl3 what is the concentration of chloride ion in the final solution?
Keep in mind that concentration (mol/L) = (# of moles) / (volume (L) ) Find the volume in litres is easy: 25.0mL + 55.5mL = 80.5 mL = 0.0805 L Now we have to find the number of moles of Chlorine (Cl) moles of Cl in 25.0mL of NH4Cl = (25.0mL)(1 L/1000mL)(0.2450mol NH4Cl/1L)(1 mol Cl/1 mol NH4Cl) = 0.006125 mol Cl moles of Cl in FeCl3= (55.5mL)(1 L/1000mL)(0.1655mol FeCl3/1 L)(3 mol Cl/ 1 mol FeCl3) = 0.02755575 mol Cl Total moles Cl = 0.006125 + 0.02755575 = 0.03368075 mol Cl Concentration = (0.03368075/0.0805) = 0.418 mol/L Cl
If you have a 300ml of a 15 percent hydrochloric acid solution in dilute the solution to 1000ml with sterile water what percent should appear on the label?
The concentration of the diluted solution will be 15(300/1000) = 4.5 %, if the percent is expressed on a weight/volume basis.
What is 5 percent of 1000ml?
50ml Way to find: 5/100 * 1000ml
If you have a 70 solution of dextrose 1000ml. how many kg of dextrose is in 400 ml of this solution?
28
How many calories does 1000ml of 5 percent dextrose have?
170
What percent is a solution containing 1000mg in 1000ml total?
The answer would depend in part on the densities of the solvent and the solute.
Is 10ml 1 percent of 1000ml?
Take the ratio of (10ml/1000ml) and multiply by 100 to find the percentage. It turns out to be (10/1000) x 100 = 1000/1000 = 1% and you are right - 10ml is 1% of 1000ml
What is the molality of a solution in which 0.3 moles of solute is dissolved in 1000ml of solvent?
yes
Sodium chloride 0.9 1000ml contains how much sodium chloride?
0.9% means there is 0.9 grams NaCl per 100ml of solution. So 1000 ml of 0.9% sodium chloride contains 9.0 grams of NaCl.
What is the percentage of 2400mg of active drug in 1000ml?
2400 mg is what percent of 1000 ml"?
How do you prepare 0.1M iodine solution?
2grm iodine and 4grm KI add to 1000ml of water
What exactly how would you make 100 grams of a saltwater solution that is 20 percent salt tell how many grams of salt and how many grams of water you would need?
20% salt solution is the equivalent of adding 200gr salt in a 800 ml (1000ml -200ml) of water. you now have one liter of a 20% solution.
How many moles of barium chloride are in 1.5 liter of a 0.256 molar solution?
.256 molar= 256 mols of solute per 1000ml of solution. Since there are 1000ml in 1L, there are 256 mols of BaCl2 for every liter. Multiply this by 1.5 and you get a total of 384 mols of BaCl2 in 1.5L of a .256 molar solution
