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[OH-] = 3.31 log[OH-] = pOH = .51982 14-pOH = pH = 13.48
1.70
[OH-] = 1x10^-4.22 or more conventionally, [OH-] = 6.03x10^-5 M
pOH= -log(0.0220M OH) pH=14-pOH pH=12.34242268
An acidic solution will have a pOH ranging from 7 to 14
1.70
12.85 is the pOH.
1.70
[OH-] = 3.31 log[OH-] = pOH = .51982 14-pOH = pH = 13.48
1.70
The pOH is the negative log of the OH- concentration. Thus, pOH = -log 2.0x10^-2pOH = 1.699 = 1.7
The pOH is 6,4.
pH and pOH are a measure of the concentration of the hydronium ions and hydroxyl ions respectively in the solution. pH = -log[H+] pOH = -log[OH-] and they are related: pH + pOH = 14
1.70
12.85
12.85
12.85