12.85
pOH +pH=14 pOH+7.6=14 pOH=(14-7.6)=6.4
The pOH is 6,4.
pH + pOH = 14 If the pH is 3.4, the pOH is 10.6
pOH = -log[OH-] = -log(5*10^-3) = 2.3 pH = 14 - pOH = 14.0 - 2.3 = 11.7 (at 25 oC)
pH + pOH = 145.3 + pOH = 14pOH = 14 - 5.3pOH = 8.7
pOH +pH=14 pOH+7.6=14 pOH=(14-7.6)=6.4
The pOH is 6,4.
pH + pOH = 14. So pOH = 14 - 1.12 = 12.88 pOH = -log[OH-] [OH-] = 1.31 x 10-13 M
pH + pOH = 14 If the pH is 3.4, the pOH is 10.6
pOH = -log[OH-] = -log(5*10^-3) = 2.3 pH = 14 - pOH = 14.0 - 2.3 = 11.7 (at 25 oC)
pH + pOH = 145.3 + pOH = 14pOH = 14 - 5.3pOH = 8.7
[H3O+] = 10-pH = 10-(14.0-pOH) = 10-(14-7.4) = 10-(6.6) = 2.5 x 10-7 mol/L
pH + pOH = 14. So pOH = 14 - 10.95 = 3.05 pOH = -log[OH-] [OH-] = 8.91 x 10-4 M
pH + pOH = 14pH = -log 3.60x10^-10 = 9.44pOH = 14 - 9.44 = 4.56
1.7
pOH = -log(10)[OH^-] pOH = -log(10) [ 48. x 10^-2] pOH = - (-1.31875...) pOH = 1.31875... pH = 14 - pOH pH = 14 - 1.31875... pH = 12.68124... pH = 12.68
We can subtract pOH from 14, using the formula pH + pOH = 14. This is only true at 14 degrees Celsius.