# What are the possible blood types for the cross between the type B (BB or Bo?) male and AB female? # What are the possible blood types for the cross between the type B (BB or Bo?) male and AB female?
A B B-AB BB B-AB BB 50% Males, 50% female. Female genes go to the left and male to the right.
50% AB 50% BB
H H H HH HH h Hh Hh This representation has the male across the top of the Punnett square and the female along the vertical axis. The formatting is almost certainly going to be messed up once I post this, for which I apologize.
Go to Www.Google.com/images then type in punnet square for xeroderma pigmentosum scroll down and click on the one with the Red and blue male and female.
quinceanera
Colorblindness is a sex-linked trait carried on the X chromosome. Males have an X and a Y chromosome (XY) and females have two X chromosomes (XX). Normal vision is dominant over colorblindness. This means that the man must have an allele for normal vision on his only X chromosome. This also means that the woman must have two colorblind alleles on both of her X chromosomes. If we use a capital 'B' to represent normal vision and a lowercase 'b' to represent colorblindness, the genotype of the male would be XBY, and the genotype of the female would be XbXb. Now that we know the genotypes, setting up the Punnett square should be easy. Here is a direct image link to the Punnett square: http://i.imgur.com/gDfUv.png This Punnett square tells us that there is a 50% chance of having a female that has normal vision and a 50% chance of having a colorblind male.
Since you did not specify what parental cross you wished to represent this is the best I can do for you. A "normal" male would be represented as XHYo - gametes XH and Yo A male with hemophilia would be represented as XhYo - gametes Xh and Yo A female non-carrier would be represented as XHXH - gametes XH A female carrier would be represented as XHXh - gametes XH and Xh A female with hemophila would be represented as XhXh - gametes Xh
Males and females have two sex chromosomes; males have XY and females XX. If you mate a male and a female, then the male side of the punnett square will have an X and Y chromosome to donate, and the female side of the punnett square will have two X chromosomes. When you fill in the punnett square you will see that the results will be two females (XX) and two males (XY). That is therefore, a 50/50 or 1:1 ratio.
typically it's on the left, but it doesnt matter.
H H H HH HH h Hh Hh This representation has the male across the top of the Punnett square and the female along the vertical axis. The formatting is almost certainly going to be messed up once I post this, for which I apologize.
what is the answer?
Go to Www.Google.com/images then type in punnet square for xeroderma pigmentosum scroll down and click on the one with the Red and blue male and female.
quinceanera
Colorblindness is a sex-linked trait carried on the X chromosome. Males have an X and a Y chromosome (XY) and females have two X chromosomes (XX). Normal vision is dominant over colorblindness. This means that the man must have an allele for normal vision on his only X chromosome. This also means that the woman must have two colorblind alleles on both of her X chromosomes. If we use a capital 'B' to represent normal vision and a lowercase 'b' to represent colorblindness, the genotype of the male would be XBY, and the genotype of the female would be XbXb. Now that we know the genotypes, setting up the Punnett square should be easy. Here is a direct image link to the Punnett square: http://i.imgur.com/gDfUv.png This Punnett square tells us that there is a 50% chance of having a female that has normal vision and a 50% chance of having a colorblind male.
the possible combination for the F2 are: by example if we have the gene T dominant and t recessive from the father and the same gene Tt from the mother . the gene possible will be TT,Tt,Tt and tt.
Circle stands for female and square stands for male.
Since you did not specify what parental cross you wished to represent this is the best I can do for you. A "normal" male would be represented as XHYo - gametes XH and Yo A male with hemophilia would be represented as XhYo - gametes Xh and Yo A female non-carrier would be represented as XHXH - gametes XH A female carrier would be represented as XHXh - gametes XH and Xh A female with hemophila would be represented as XhXh - gametes Xh
It would be exactly the same way you make any punnet square. Just remember that the Y chromosome on males is recessive to the X chromosome. So for example, if a certain recessive phenotype is carried on the X chromosome, and the offspring is a male, the male will show that phenotype (because Y is recessive to X). However if it is a female, she will not show the phenotype because we said it is a recessive X linked phenotype.
Female female male male female Male male male female Male male female