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From your description, this sounds like it is a sine wave offset to 10A, so the peak is at 20A, and the min is at 0? For this case, you have 10A DC (RMS) wave and a 10A Peak - neutral AC wave; The RMS value of the AC wave is: 10/2*sqrt(2) = 3.54A. So the RMS amplitude of this wave is 13.54A.
wattage is voltage and amperage multiplied. example V/A=W or 120v x 20a=2400 watts
Line current = 10MW / 500kV = 20A Assuming the 1000 ohms is the resistance of the entire transmission line, end to end. Power loss = line current ^ 2 * line resistance = 20A ^ 2 * 1000 ohms = 400 KW
Yes it will operate it fine.
From your description, this sounds like it is a sine wave offset to 10A, so the peak is at 20A, and the min is at 0? For this case, you have 10A DC (RMS) wave and a 10A Peak - neutral AC wave; The RMS value of the AC wave is: 10/2*sqrt(2) = 3.54A. So the RMS amplitude of this wave is 13.54A.
HOW TO CONNECT AN AMMETER Always connect an ammeter in SERIES in a circuit. Always ensure that the ammeter has a higher reading range than the expected current load, including start-up spikes. An ammeter expected to read a steady current of 13A should have a max range of 20A.
typically the ratio is on the current transformer it will say something like 100:5 witch means 5a meter becomes 100A full scale the 5 instead of a 1 gives you a hint about the capacity of the transformer its 20:1 so you could use it to make a 1A meter into a 20A but making a 10A meter into a 200A may lead to problems (accuracy or power)
2
20a + 45 = 5(4a + 9)
-4(5a-3) = -20a + 12
It cannot be simplified any further, so it is: 5a³ + 15a² + 20a
12
The cast of 20a Stories from a Bus - 2007 includes: Kris Cuppens as Driver
F9 and its a 20A fuse :)
20a^2
20a
no