Want this question answered?
Its 16bit microprocessor,and-> the 8086 has a 16bit databus 20bit address bus-> the intel 8086,is designed to operate in two modes namely(1) minimum mode(2) maximum mode
Its MRDC (memory read control) it is a maximum mode pin in 8086 microprocessor
The operand addressing modes of the 8086/8088 are ...ImmediateRegisterDirectIndirectWithin the Indirect category there is ...BaseIndexBase + IndexBase + DisplacementIndex + DisplacementBase + Index + Displacement
there are five addressing modes in 8086 they are : 1->direct addressing 2->Indirect addressing 3->index addressing 4->immediate addressing 5->register addressing
Addressing modes of 8051 are 1.Immediate Addressing Mode 2.Register Addressing Mode 3.Register Indirect Addressing Mode 4.Direct Addressing Mode 5.Implied Addressing Mode and 6.Relative Addressing Mode
It is register addressing mode, as it moves the content of HL to PC which is data and not address.
Immediate addressing mode is when one of the operands is "immediately" located after the opcode. It is more correct to say that the operand is part of the instruction.
Immediate addressing mode is when one of the operands is "immediately" located after the opcode. It is more correct to say that the operand is part of the instruction.
because the operand is available in the instruction itself
literal and absolute direct are the registers
minimum mode and maximum mode
Yes, the 8086/8088, unlike its more advanced successors, has only one operational mode. Since the successors were not around when it was designed, there is no name for this mode, but, in the context of the successors, it is called REAL mode, although it is subtly different than the successors in how it handles RESET. (CS=FFFF, IP=0000, owing to the fact that it is, in reality, only a 16 bit computer.)