There is no equation. Calcium-42 is stable and does not decay. Calcium is also much to light for alpha decay, which requires elements heavier than nickel, so no isotope of calcium undergoes alpha decay.
224
Since an alpha particle is simply two protons and two neutrons bound together, or He2+, the alpha decay of selenium-78 is easily determined. Selenium-78 has 34 protons and 44 neutrons. Subtract 2 from each of these due to the loss of the alpha particle and you have 32 protons and 42 neutrons. This new atom is germanium-74.
SMD
Calcium has atomic number 20, which means that all calcium atoms have 20 protons in their atomic nuclei. Neutral calcium atoms also have 20 electrons. Isotopes of calcium vary in the number of neutrons in their atomic nuclei, and are named for their mass number, which is the sum of the protons and neutrons in the nucleus. You can calculate the number of neutrons (N) in an isotope by subtracting the number of protons (atomic number) from the mass number. N = 42 - 20 = 22, therefore, a calcium-42 isotope has 20 protons, 20 electrons, and 22 neutrons.
They have different masses because the number of neutrons varie. All these are called "isotopes". Each neutron weighs a certain amount, and with more or less neutrons, the mass changes
Ra22688 = Rn22286 + (a)42+ (a)= an alpha particle, i can't do the symbol here
I would assume potassium-42 decays into calcium-42 via beta decay. Potassium-42 --> Calcium-42 + electron
An alpha particle
224
Since an alpha particle is simply two protons and two neutrons bound together, or He2+, the alpha decay of selenium-78 is easily determined. Selenium-78 has 34 protons and 44 neutrons. Subtract 2 from each of these due to the loss of the alpha particle and you have 32 protons and 42 neutrons. This new atom is germanium-74.
224 rn 86
SMD
86 - 42 = 44
7x=42 x=42/7 or, x=6
how do you set the equation in algebra to solve 42 nickles to 19 dimes
The equation 7 times 42 is equal to 294.
294