224
No, it decays via beta minus into Actinium 228.
The equation for the beta decay of 228Ra is: 88288Ra --> 89288Ac+ -10e
where the -10e is a negative beta particle or electron. 224****
Ra22688 = Rn22286 + (a)42+
(a)= an alpha particle, i can't do the symbol here
226Ra-------alpha particle-------222Rn (radon, a radioactive gas)
Plutonium-241 decays by both beta- and alpha decay. For beta- decay the equation is ...94241Pu -> 95241Am + e- + v-eNot asked but answered for completeness sake, for alpha decay the equation is ...94241Pu -> 92237U +24He2+
The equation for the alpha decay of 234U is: 92234U --> 90230Th + 24He representing the alpha particle as a helium nucleus. 234U also decays by spontaneous fission, but the results are somewhat unpredictable, so there is no standard equation.
Four times of the hydrogen atom.
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
A:Uranium - 238 --> Pb - 206 + Alpha + Beta note this is a simplified over all reaction, the actual process involves around 15 steps...A:The equation for the alpha decay of 238U is: 92238U --> 90234Th + 24HeThe alpha particle is represented as an He nucleus.
Uranium-239 does NOT decay by alpha decay, it decays only by beta and gammadecay.
The equation for the alpha decay of 235U is: 92235U --> 90231Th + 24He representing the alpha particle as a helium nucleus. 235U also decays by spontaneous fission, but the results are somewhat unpredictable, so there is no standard equation.
Plutonium-241 decays by both beta- and alpha decay. For beta- decay the equation is ...94241Pu -> 95241Am + e- + v-eNot asked but answered for completeness sake, for alpha decay the equation is ...94241Pu -> 92237U +24He2+
Alpha emission means that an alpha particle (2 protons + 2 neutrons) are emitted, so the original nucleus has 2 protons and 2 neutrons more.
The equation for the alpha decay of 234U is: 92234U --> 90230Th + 24He representing the alpha particle as a helium nucleus. 234U also decays by spontaneous fission, but the results are somewhat unpredictable, so there is no standard equation.
There is no thallium-230 isotope.Also no thallium isotope decays by alpha decay, the unstable isotopes all decay either by K capture or beta decay.
give off nuclear radiation
The equation for the alpha decay of 233Pu:94233Pu --> 92229U + 24He2+where the alpha particle is represented as a helium nucleus.Note that 233Pu decays by alpha decay with a probability of only 0.12%. The other 99.88% is Beta+ decay.
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
The equation for the alpha decay of 213At: 85213At --> 83209Bi + 24He where the alpha particle is represented as a helium nucleus.
The equation for the alpha decay of 265Bh is:107265Bh --> 105261Db + 24He where the 24He is an alpha particle or helium nucleus.
Th-230(alpha)Ra-226.