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The nuclear equation for the alpha decay of 242Pu is: ^24294Pu -> ^23892U + ^4He2 This equation shows that the nucleus of 242Pu decays into a nucleus of 238U and an alpha particle, which is a helium-4 nucleus.
The equation for the alpha decay of 234U is: 92234U --> 90230Th + 24He representing the alpha particle as a helium nucleus. 234U also decays by spontaneous fission, but the results are somewhat unpredictable, so there is no standard equation.
What is missing is the type of decay that occurs during the transformation. For example, uranium-238 decays into thorium-234 through alpha decay, so the missing component would be the emission of an alpha particle in the balanced equation.
A:Uranium - 238 --> Pb - 206 + Alpha + Beta note this is a simplified over all reaction, the actual process involves around 15 steps...A:The equation for the alpha decay of 238U is: 92238U --> 90234Th + 24HeThe alpha particle is represented as an He nucleus.
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
Uranium-239 does NOT decay by alpha decay, it decays only by beta and gammadecay.
The nuclear equation for the alpha decay of 242Pu is: ^24294Pu -> ^23892U + ^4He2 This equation shows that the nucleus of 242Pu decays into a nucleus of 238U and an alpha particle, which is a helium-4 nucleus.
The equation for the alpha decay of 235U is: 92235U --> 90231Th + 24He representing the alpha particle as a helium nucleus. 235U also decays by spontaneous fission, but the results are somewhat unpredictable, so there is no standard equation.
The equation for the alpha decay of 234U is: 92234U --> 90230Th + 24He representing the alpha particle as a helium nucleus. 234U also decays by spontaneous fission, but the results are somewhat unpredictable, so there is no standard equation.
The nuclear equation for the decay of Po-210 undergoing 2 alpha decays followed by a beta decay and another alpha decay is: Po-210 -> Pb-206 + 4 He-4 + 2 e-1 + 2 v This equation represents the series of decays that result in the transformation of Po-210 into Pb-206, with the emission of two helium nuclei (alpha particles), two electrons, and two neutrinos.
Alpha emission means that an alpha particle (2 protons + 2 neutrons) are emitted, so the original nucleus has 2 protons and 2 neutrons more.
Gamma rays do not have mass or charge, so they do not contribute to the balance of a nuclear equation that involves the emission of an alpha particle. The alpha particle carries away the mass and charge necessary to balance the nuclear equation.
In alpha decay, the nucleus emits an alpha particle (helium nucleus) consisting of 2 protons and 2 neutrons. Thallium-230 undergoes alpha decay to produce an alpha particle (helium-4 nucleus) and become lead-226. The balanced nuclear equation for this process is: ([^{230}{81}Tl \rightarrow ^{4}{2}He + ^{226}_{82}Pb]).
The balanced nuclear equation for the alpha decay of thorium-230 is: ^230Th → ^226Ra + ^4He
The equation for the alpha decay of 233Pu:94233Pu --> 92229U + 24He2+where the alpha particle is represented as a helium nucleus.Note that 233Pu decays by alpha decay with a probability of only 0.12%. The other 99.88% is Beta+ decay.
The equation for alpha decay of mercury-201 is: ^201Hg -> ^197Au + ^4He This means that mercury-201 decays into gold-197 and helium-4 by emitting an alpha particle.
give off nuclear radiation