There is no thallium-230 isotope.
Also no thallium isotope decays by alpha decay, the unstable isotopes all decay either by K capture or beta decay.
The balanced nuclear equation for the alpha decay of thorium-230 is: ^230Th → ^226Ra + ^4He
Po-216- -----------------> Pb-212
210 4 214 84 PO -------> 2 alpha + 86 RN
100Fm254 .........> 98Cf250 + 2He4
The nuclear equation for the decay of Po-210 undergoing 2 alpha decays followed by a beta decay and another alpha decay is: Po-210 -> Pb-206 + 4 He-4 + 2 e-1 + 2 v This equation represents the series of decays that result in the transformation of Po-210 into Pb-206, with the emission of two helium nuclei (alpha particles), two electrons, and two neutrinos.
The equation for the alpha decay of 233U is: 92233U --> 90229Th + 24He representing the alpha particle as a helium nucleus. 223U can also undergo fission, but since this is an rather unpredictable process, there is no standard equation.
Gamma rays do not have mass or charge, so they do not contribute to the balance of a nuclear equation that involves the emission of an alpha particle. The alpha particle carries away the mass and charge necessary to balance the nuclear equation.
The balanced nuclear equation for the alpha decay of thorium-230 is: ^230Th → ^226Ra + ^4He
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
The equation for the alpha decay of 213At: 85213At --> 83209Bi + 24He where the alpha particle is represented as a helium nucleus.
The equation for the alpha decay of 265Bh is:107265Bh --> 105261Db + 24He where the 24He is an alpha particle or helium nucleus.
The nuclear equation for the alpha decay of 242Pu is: ^24294Pu -> ^23892U + ^4He2 This equation shows that the nucleus of 242Pu decays into a nucleus of 238U and an alpha particle, which is a helium-4 nucleus.
Uranium-239 does NOT decay by alpha decay, it decays only by beta and gammadecay.
Radium-226--------------------Radon-222 + alpha
A:Uranium - 238 --> Pb - 206 + Alpha + Beta note this is a simplified over all reaction, the actual process involves around 15 steps...A:The equation for the alpha decay of 238U is: 92238U --> 90234Th + 24HeThe alpha particle is represented as an He nucleus.
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
Po-216- -----------------> Pb-212