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There is no thallium-230 isotope.

Also no thallium isotope decays by alpha decay, the unstable isotopes all decay either by K capture or beta decay.

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What is the nuclear decay equation for uranium 233?

The equation for the alpha decay of 233U is: 92233U --> 90229Th + 24He representing the alpha particle as a helium nucleus. 223U can also undergo fission, but since this is an rather unpredictable process, there is no standard equation.


Why does the presence of gamma rays not affect how a nuclear equation of alpha is balance?

Gamma rays do not have mass or charge, so they do not contribute to the balance of a nuclear equation that involves the emission of an alpha particle. The alpha particle carries away the mass and charge necessary to balance the nuclear equation.


What is the balanced nuclear equation for the alpha decay of thorium 230?

The balanced nuclear equation for the alpha decay of thorium-230 is: ^230Th → ^226Ra + ^4He


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The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.


What is the nuclear decay equation for astatine 213?

The equation for the alpha decay of 213At: 85213At --> 83209Bi + 24He where the alpha particle is represented as a helium nucleus.


What is the nuclear decay equation for bohrium-265?

The equation for the alpha decay of 265Bh is:107265Bh --> 105261Db + 24He where the 24He is an alpha particle or helium nucleus.


What is the nuclear equation for the alpha decay of 242 Pu?

The nuclear equation for the alpha decay of 242Pu is: ^24294Pu -> ^23892U + ^4He2 This equation shows that the nucleus of 242Pu decays into a nucleus of 238U and an alpha particle, which is a helium-4 nucleus.


What is the nuclear equation for the alpha decay of uranium 239?

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What is the decay process does radium 226 undergo including the nuclear changes that occur?

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What is the nuclear equation of the decay of uranium 238?

A:Uranium - 238 --> Pb - 206 + Alpha + Beta note this is a simplified over all reaction, the actual process involves around 15 steps...A:The equation for the alpha decay of 238U is: 92238U --> 90234Th + 24HeThe alpha particle is represented as an He nucleus.


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If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).


How do you write a balanced nuclear equation for the alpha decay of polonium -216?

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