Moles = weight in grams / atomic weight So the moles in 0.54 g of He = 0.54 / 4.002 = 0.14 moles
261 g = 0.261 kgTo convert from g to kg, divide by 1000.
M = g/L 20 = g/0.05 20 * .05 = g 1.0 = g of solute
6675 moles Moles = weight (in g) / atomic weight = 26700 g / 4 = 6675 moles
5 moles of carbon is 60,055 g.5 moles of sodium is 114,949 g.
Moles = weight in grams / atomic weight So the moles in 0.54 g of He = 0.54 / 4.002 = 0.14 moles
Moles = Mass (g) x Molar mass (g)
Calculated by dividing mass (in grams) by atomic mass of Zn: 3.45(g) / 65.38(g/mole) = 0.0528 mole
Molecular mass of NaCl = 23.0 + 35.5 = 58.5 Amount of NaCl = 42/58.5 = 0.718mol
261 g = 0.261 kgTo convert from g to kg, divide by 1000.
M = g/L 20 = g/0.05 20 * .05 = g 1.0 = g of solute
First find out how many grams in 1 mole:Nitrogen is 14.007 g/mol, Hydrogen is 1.0079 g/mol, and Chlorine is 35.453 g/molThere are 4 Hydrogen, so 14.007 + 4*(1.0079) + 35.453 = 53.4916 g/mol(50 g)/(53.4916 g/mol) = 0.9347 moles
Moles = weight in g / atomic weight. So moles in 24.7 g of Ar = 24.7 / 39.948 = 0.62 moles
The number of moles is given by :n = m / Mn = ( 4.5 g ) / ( 169.9 g / mol ) = 0.02649 moles
6675 moles Moles = weight (in g) / atomic weight = 26700 g / 4 = 6675 moles
5 moles of carbon is 60,055 g.5 moles of sodium is 114,949 g.
Balanced Formula:2Mg + O2 --> 2MgOMole ratio:2 : 1 : 2Givens:.486 g oxygen.738 g magnesium24.3 g = atomic mass of magnesium16.0 g = atomic mass of oxygen40.3 g = molecular mass of magnesium oxideFind the amount (in moles) of Magnesium oxide that oneelement will make:(.486 g O) / (16.0 g O) × (2 moles MgO)= .0608 moles MgO(.783 g Mg) / (24.3 g Mg) = .0322 moles MgOThere is less MgO produced with magnesium than oxygen; therefore, magnesium is the limiting reactant and the oxygen is the excess reactant. The magnesium determines how much Magnesium oxide is produced. It would be good to get .0608 moles of MgO, but there isn't enough magnesium. So the amount of MgO produced will be determined on the amount of Magnesium.Convert moles of MgO produced with the amount of oxygen to grams:.0322 mol MgO (40.3 g) = 1.30 grams of MgO produced--------------------------------------------------------------------------------------------------------You will need 3 moles of oxygen if you start with six moles of magnesium. This will allow you to produce 6 moles of magnesium oxide.Source: (e2020)