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How many moles of silver are present in 32.46g of AgNO3?
To find the number of moles of silver in 32.46g of AgNO3, first calculate the molar mass of AgNO3 (169.87 g/mol). Then, divide the given mass by the molar mass to find the number of moles (32.46g / 169.87 g/mol ≈ 0.191 moles). Since there is one mole of Ag in one mole of AgNO3, there are 0.191 moles of silver present.
How many moles of AgNO3 does 85 grams of AgNO3 represents?
To find the number of moles, you need to divide the given mass (85 grams) by the molar mass of AgNO3 (169.87 g/mol). 85 grams of AgNO3 represents 0.500 moles.
How many moles in 4.50 grams of silver nitrate?
To find the number of moles in 4.50 grams of silver nitrate (AgNO3), you first need to calculate the molar mass of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. Then, use the formula: moles = mass/molar mass. So, 4.50 grams of AgNO3 is equal to 0.0265 moles.
What is the molar mass of 2AgNO3?
The molar mass of silver nitrate (AgNO3) is approximately 169.87 g/mol. Multiplying this by 2 gives a molar mass of 339.74 g/mol for 2 moles of AgNO3.
How many moles of silver nitrate do 2.8881015 formula untied equal?
To find the number of moles in 2.8881015 formula units of silver nitrate, you first need to know the molar mass of silver nitrate (AgNO3), which is 169.87 g/mol. Then, you can use the formula: moles = formula units / Avogadro's number. Therefore, moles = 2.8881015 / 6.022 x 10^23 = 4.79 x 10^-24 moles.
How many moles of silver of ions are presented in 32.46 g of AgNO3?
The number of moles is 0,19.
How many moles of silver are present in 32.46g of AgNO3?
To find the number of moles of silver in 32.46g of AgNO3, first calculate the molar mass of AgNO3 (169.87 g/mol). Then, divide the given mass by the molar mass to find the number of moles (32.46g / 169.87 g/mol ≈ 0.191 moles). Since there is one mole of Ag in one mole of AgNO3, there are 0.191 moles of silver present.
How many moles of AgNO3 does 85 grams of AgNO3 represents?
To find the number of moles, you need to divide the given mass (85 grams) by the molar mass of AgNO3 (169.87 g/mol). 85 grams of AgNO3 represents 0.500 moles.
How many moles of AgCl will be produced from 83.0 g of AgNO3 assuming NaCl is available in excess?
The balanced chemical equation for this reaction is: AgNO3 + NaCl -> AgCl + NaNO3 From this equation, we can see that 1 mole of AgNO3 produces 1 mole of AgCl. Since the molar mass of AgNO3 is 169.87 g/mol, 83.0 g of AgNO3 is equivalent to 0.488 moles. Therefore, 0.488 moles of AgCl will be produced.
How many moles in 4.50 grams of silver nitrate?
To find the number of moles in 4.50 grams of silver nitrate (AgNO3), you first need to calculate the molar mass of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. Then, use the formula: moles = mass/molar mass. So, 4.50 grams of AgNO3 is equal to 0.0265 moles.
How do you convert 22.6g AgNO3 to moles?
To convert grams to moles, you need to divide the given mass by the molar mass of the substance. The molar mass of AgNO3 is approximately 169.87 g/mol. Therefore, to convert 22.6g of AgNO3 to moles, you would divide 22.6g by 169.87 g/mol to get approximately 0.133 moles of AgNO3.
How many grams of AgNO3 are required to make 500.0 mL of a 0.10 M solution?
Ah, what a lovely question! To make a 0.10 M solution of AgNO3 in 500.0 mL, we can use the formula: moles = molarity x volume (in liters). First, convert 500.0 mL to liters by dividing by 1000. Then, multiply the molarity (0.10 M) by the volume in liters to find the moles of AgNO3 needed. Finally, convert moles to grams using the molar mass of AgNO3. Happy calculating!
How much does 13.0 moles of AgNO3 weigh?
13 multiplied by 169.87 (g/mol) = 2208.3g
How many moles of BaCl2 barium chloride is necessary to react with the 7.5 moles AgNo3 silver nitrate in 2AgNO3 BaCl-- 2AgCl Ba(NO3)2?
3,75 moles barium chloride
What is the molar mass of 2AgNO3?
The molar mass of silver nitrate (AgNO3) is approximately 169.87 g/mol. Multiplying this by 2 gives a molar mass of 339.74 g/mol for 2 moles of AgNO3.
How many silver atoms would be in 4.55 moles of AgNO3?
To find the number of silver atoms in 4.55 moles of AgNO3, first calculate the molar mass of AgNO3 which is 169.87 g/mol. Then set up a ratio using Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. The calculation would be 4.55 moles x (6.022 x 10^23 atoms/mol) = 2.74 x 10^24 silver atoms in 4.55 moles of AgNO3.
How many molecules are there in 65 g of silver nitrate (AgNO3)?
Well, because you have 65g of AgNO3, you have .3826 moles of silver nitrate. This is found by dividing the number of grams you have by the molar mass of silver nitrate (169.9g/mol). Once you know how many moles there are you can then multiply by Avogodro's number (6.022x1023) to obtain the number of molecules. In this case it is 2.304x1023 molecules.
