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You can approach this from a stoichiometry perspective or a proportions perspective.

Before you do one of these methods, you want to calculate the molar mass of ethane. Ethane has two carbons and six hydrogens. Using the Periodic Table, we find that the molar mass is 30.06 g/mol.

If you do the stoichiometry, we have (1 mol)×(30.06 g/mol)×(312 kJ / 6.0 g) = 1600 kJ.

Or you can say that if 6.0 g = 312 kJ, then 30.06 g = x kJ where "x" is your unknown, or (6 g / 312 kJ) = (30.06 g / x kJ). Solving for x provides 1600 kJ.

Both involve the same calculations but have slightly different modes of thinking. Note that the answer has only two significant digits because 6.0 has only two significant digits. We can assume that 1 mole is a discrete value and that our answer shouldn't have one significant digit.

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Q: What is the amount of heat released in the combustion of 1mol of ethane if 6.0g produces 312KJ?
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