0.5 amps
If there is nothing else in the circuit, then the voltage drop across the resistor will be the full supply voltage of 5 volts. The size of the resistor does not matter in this case - it will always be 5 volts.
If by power supply you mean a voltage source, it really won't matter that the resistor is removed. The voltage source will provide infinite current, instantly charging the capacitor so that the capacitor's voltage is equal to the source.Alternative AnswerIf you are referring to an a.c. circuit, then a load current will continue to flow with its value being determined by the capacitive reactance of the circuit, and the resulting phase angle will lead the supply voltage be very close to 90 degrees.
The question has just stated clearly that the applied voltage is 12 volts DC.Provided that the power supply is capable of maintaining its output voltage while supplying some current ... i.e. that the effective internal resistance of the power supply is small ... and that the 2.7 ohm resistor is the only external element connected to the power supply's output, the voltage across the resistor is exactly 12 volts DC.The current through the resistor ... supplied by the 12 volt DC supply ... is 12/2.7 = 4.44 Amperes (rounded).The power dissipated by the resistor ... supplied by the DC supply ... is 122 / 2.7 = 53.23 watts !
A current limiter. Commonly used in well designed power supplies to make the power supply "Fold over" if output current exceeds a safe value. Commonly use a low value resistor in series with the output, and a circuit that senses the voltage across it. Although the above answer describes a circuit to limit current, the device that limits the amount of current flowing through it is a resistor.
If there are only a resistor and a capacitor in the circuit, then the phase shift will indeed be between 0 and 90 degrees. When the resistor and capacitor are in series, the phase shift will be negative when the capacitor is connected to a source voltage and the resistor is the load. The phase shift will be positive when the resistor is connected to the source. The lower the values of R and C, the higher the frequency bandwidth.With the resistor and capacitor connected in series and the two parts connected to a current source, the phase shift will be negative. At high frequencies, the output voltages is lower, and the circuit appears as a very low impedance. At low frequencies, the circuit looks more like a resistor. Again, the phase shift will be between 0 and 90 degrees.CommentThe correct term is phase angle, not 'phase shift'. By definition, the phase angle is the angle by which the load current leads or lags the supply voltage. For an RC circuit, the current leads the voltage, so the phase angle is a leading phase angle.
The electric heater is basically a resistor, designed to have the right resistance to draw the required current. So a 2 kW heater designed for a 230 v supply is really a resistor of 28.8 ohms, so when it's connected the current is 8 amps and the power is 2 kW.
a meter uses its own supply to measure resistance. you dont have to remove the resistor from the circuit but you must isolate it from the circuit supply to get an accurate reading.
If a 9V supply is connected to a 100-ohm resistor, then the current is not 2 Amps,or even close to it.I = E/R = 9/100 = 0.09 amp.
Electricity is the interaction of many components. These include electric charges, electric fields, electric potentials, electric currents, and electromagnets.
If there is nothing else in the circuit, then the voltage drop across the resistor will be the full supply voltage of 5 volts. The size of the resistor does not matter in this case - it will always be 5 volts.
a power supply (eg: battery) and a load (eg: resistor) even a piece wire shorting two terminals of the power supply is a closed circuit
you need an electrical supply and a load. nice and simple.
It slows down the speed of the electrons , which are all passing through the resistor
The resistor has gone to open ( or possibly short ) circuit. Remove ( if possible ) the resistor from the circuit and measure its stand alone resistance. If the resistor measures infinate then you need to replace it with whatever the circuit asks for. ie 10ohms, 15 ohms etc. Make sure you test the simple things first such as power supply and ensure that you are receiving power to at least one side of the resistor. If you are working on an electronic card then make sure you check your ' circuit paths ' you may have a burnt track. Test your continuity across your paths. Don't nescessarily concerntrate on the resistor itself it may not have power on it due to another component failure or circuit failure. Cheers.
Power source such as a battery if u pluged it in it will supply energy to drive electric charges around a circuit
The current flows from the positive of the power supply, through whatever is placed in its path eg resistor, bulb, closed switch etc to the negative terminal of the power supply - going 'round the block' to the point where it started or taking a 'circuit' in its journey
circuit is the complete path of an electric current including the source of electric energy.